At start ( t = 0 nanoseconds ) :
E ( t = 0 ) = 2.645 J
E ( t = 1 ) = 6.290 J
E ( t = 1 ) : E ( t = 0 ) = 6.290 : 2.645 = 2.37
Also:
E ( t = 2 ) : E ( t = 1 ) = 14.909 : 6.290 = 2.37
E ( t = 3 ) ; E ( t = 2 ) = 35.335 : 14.909 = 2.37
Therefore, the formula for calculating the energy of the system is:
E ( t ) = 2.645 * 2.37 ^ t
The answer is 4) exponential growth.
Answer:
the sum of exterior angles of a polygon is 360°
Answer:
Step-by-step explanation:
(-4,0) ; (-7, -14)
![d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(-7-[-4])^{2}+(-14-0)^{2}}\\\\ =\sqrt{(-7+4)^{2}+(-14)^{2}}\\\\=\sqrt{(-3)^{2}+(-14)^{2}}\\\\=\sqrt{9+196} \\\\=\sqrt{205} \\\\=14.3178](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_%7B2%7D-x_%7B1%7D%29%5E%7B2%7D%2B%28y_%7B2%7D-y_%7B1%7D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%28-7-%5B-4%5D%29%5E%7B2%7D%2B%28-14-0%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B%28-7%2B4%29%5E%7B2%7D%2B%28-14%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%28-3%29%5E%7B2%7D%2B%28-14%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B9%2B196%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B205%7D%20%5C%5C%5C%5C%3D14.3178)
Ok, so;
Let me draw the figure here below:
We know that the area of a circle can be found using the next equation:
Area = πr².
Where r is the radius and π is a number.
So, the area of this circle, will be:
Area = π(1km)²
Area = π km²