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Blizzard [7]
2 years ago
11

Which of the following reasons helps explain why − 7/0 is not a rational number.

Mathematics
2 answers:
ycow [4]2 years ago
8 0

Answer:

you

Step-by-step explanation:

kvv77 [185]2 years ago
7 0

Hi!

The number has a zero in the denominator.

If a number has a 0 in it's denominator, then it's not rational

Division by 0 is undefined.

Hope this helps you!

~Just a felicitous girlie

#HaveAWonderfulDay

SilentNature

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Harry is trying to solve the equation y = 2x^2 − x − 6 using the quadratic formula. He has made an error in one of the steps bel
Bond [772]
He made a mistake in step #2. It seemed to be a trivial mistake because it involved signs, but it still had a great impact. Since step#2, his solution was already wrong.

Instead of
(-1)²-4(2)(-6) = 1 + 48 = 49

What he did is
(-1)²-4(2)(-6) = -1 + 48 = 47
4 0
3 years ago
Multiply y^2-16/2y . 5y/y-4
alisha [4.7K]
So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
=y^2-4^2=(y+4)(y-4)
=5(y+4)(y-4)
=5(y+4)(y-4)/2(y-4)
Cancel the common factor y-4
=5(y+4)/2
Answer: 5(y+4)/2



5 0
3 years ago
Which equation represents a circle with a center at (–4, 9) and a diameter of 10 units?
ale4655 [162]

Answer:

(x + 4)^2 + (y – 9)^2 = 25

Step-by-step explanation:

The standard form for a circle is

(x - h)^{2} + (y - k)^{2}  = r^{2}     where (h, k) is the center and r is the radius

In your case, h = -4 and k = 9 and r = 5

So, (x + 4)^2 + (y – 9)^2 = 25

7 0
3 years ago
Read 2 more answers
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Montano1993 [528]
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y = x - 1

|x² - 3x + 1| = x - 1
|x² - 3x + 1| = ±1(x - 1)
|x² - 3x + 1| = 1(x - 1)       or      |x² - 3x + 1| = -1(x - 1)
|x² - 3x + 1| = 1(x) - 1(1)    or    |x² - 3x + 1| = -1(x) + 1(1)
|x² - 3x + 1| = x - 1        or         |x² - 3x + 1| = -x + 1
  x² - 3x + 1 = x - 1         or          x² - 3x + 1 = -x + 1
        - x        - x                                + x         + x
  x² - 4x + 1 = -1           or            x² - 2x + 1 = 1
              + 1 + 1                                       - 1 - 1
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                      2(1)                                             2(1)
  x = 4 ± √(16 - 4)            or            x = 2 ± √(4 - 0)
                 2                                                 2
  x = 4 ± √(12)              or               x = 2 ± √(4)
             2                                                  2
 x = 4 ± 2√(3)               or               x = 2 ± 2
             2                                                2
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y = 2 - 1 + √(3)     or      y = 2 - 1 - √(3)          or           y = 1      or       y = -1
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3 years ago
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