For a smoothing constant of 0.2
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90
Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12
The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80
Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17
The mean forecast for period 11 is 53.56
Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
There are 60 players on football team that are not seniors.
Step-by-step explanation:
<u>Method 1:</u>
Given
Total students = 84
Also given that
2 out of 7 are seniors
Which is 2/7
So in order to find the total number of seniors we will multiply the whole number of students to 2/7
So there are 24 seniors on the football team.
Players that are not seniors = 84 - 24 = 60
There are 60 players who are not seniors.
<u>Method 2:</u>
We can divide the total number by 7, to get how many sets of 7 players will be there
= 84/7 = 12
Now,
Multiplying 12 with 2 will give us the number of seniors in football team.
12*2 = 24 seniors
So,
Not seniors =84-24 = 60
Keywords: Percentage, Units
Learn more about percentage at:
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Answer:
The answer is 200km
Step-by-step explanation:
250\5=50,50×4=200
Answer:
since it goes down a certain way and it goes down then B will go the same way as a evil ghost literally down to the phone the top right to the left like see if I just a little bit shorter Jay will go all the way up to age and we will go to k
Answer:
False
Step-by-step explanation:
15 isn't divisible by 10
