Generally, A relation is considered to be a function if it can be shown that each value from the set of first components of ordered pairs is connected with precisely one value from the set of second components of ordered pairs.

In conclusion, You may also consider this in terms of the fact that there is one and only one y associated with each x.

Although it is obvious that this is not the case, the calculation for the vertical line nevertheless uses these terms.

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3 0

1 year ago

Sabra went for a long hike and burned 845 calories in 3 1/4 hours.Nelson decided to go for a bike ride. He burned 1,435 calories

sergey [27]

Answer:

Nelson burned the most calories per hour

Explanation:

To solve this question, we will get the amount calories burned by each in one hour and then compare the two values

To do this, we will divide the total amount of calories burned by the total time

1- For Sabra:

We are given that she burnt 845 calories in $3\frac{1}{25}$ (which is equivalent to 3.25) hours

Therefore:

Calories burnt in an hour = $\frac{845}{3.25}=260$ calories/hour

2- For Nelson:

We are given that he burnt 1435 calories in $4\frac{7}{8}$ (which is equivalent to 4.875) hours

Therefore:

Calories burnt in an hour = $\frac{1435}{4.875}=294.36$ calories/hour

3- Comparing the two values:

From the above calculations, we can deduce that Nelson burned the most calories per hour

Hope this helps :)

3 0

3 years ago

Which statement best describes g(x) = 3x + 6 - 8 and the parent function f(x) = } ?

kumpel [21]

Answer:

In general gf(x) is not equal to fg(x)

Some pairs of functions cannot be composed. Some pairs of functions can be composed only for certain values of x.

Only with they can be composed some values of x are the ranges of g(x) and f(x) are the same, and their domains are also the same. Or else lies inside it.

Step-by-step explanation:

g(x) = 3x + 6 - 8, f(x) = √x.

The domain of a composed function is either the same as the domain of the first function, or else lies inside it

The range of a composed function is either the same as the range of the second function, or else lies inside it.

Or vice versa

Now only positive numbers, or zero, have real square roots. So g is defined only for numbers

greater than or equal to zero. Therefore g(f(x)) can have a value only if f(x) is greater than or

equal to zero. You can work out that

f(x) ≥ 0 only when x ≥3/2

3 0

2 years ago