Add. x+1x+x2+5xx2+4x−5

Where would i draw my reflection

Maurinko [17]

Answer:

The coordinates for the reflection of quadrilateral ABCD is..

A'(-7,2) ----> A'(-7,-2)

B'(-7,4) ----> B'(-7,-4)

C'(-4,6) ----> C'(-4,-6)

D'(-1,6) ----> D'(-1,-6)

Step-by-step explanation:

Since it's being reflected over the x-axis, the x remains the same and the y becomes a negative.

3 0

3 years ago

Five computer program modules are ranked as M1, M2, M3, M4, and M5 according to the ascending order of effort required to debug

gulaghasi [49]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Technician selects three out of 5 systems

In C(5,3)=10ways, this can be achieved

In part a:

Space sample chooses 3 of a 5 systems

$(M_1, \ M_2,\ M_3),$ $(M_1,M_2,M_4) \ (M_1,M_2,M_5) \ (M_1,M_3,M_4) \ (M_1,M_3,M_5),$ $(M_1,M_4,M_5) \ (M_2,M_3,M_4)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5)}$

In point b:

A =MODULE WHICH INCLUDE M1 minimal amount of effort

Outcomes probable =

$(M_1,M_2,M_3),\ (M_1,M_2,M_4) \ (M_1,M_2,M_5)\ (M_1,M_3,M_4)\\\\(M_1,M_3,M_5),\ (M_1,M_4,M)5)\ =\ 6$

$\to p(A)=\frac{6}{10}\\\\$

$=0.6$

In point c:

B = highest effort that is $M_5$

Potential result=

$(M_1,M_2,M_5) \ (M_1,M_3,M_5) \ (M_2,M_3,M_5)\(M_2,M_4,M_5) \\ (M_2,M_4,M_5), \ (M_3,M_4,M_5) \ =\ 6 \\\\$

$\to B= \frac{6}{10} \\\\$

$=0.6$

$\to P(B)=10$

In point d:

$\to \ A \ intersection \ B=(M_1,M_2,M_5), \ (M_1,M_3,M_5) \ ,(M_1,M_4,M_5)$

$\to A (A \ intersection \ B) = \frac{3}{10} \\\\\ \ \ \ \ \$

$=0.3$

In point e:

$\to (A \cup B) = (M_1,M_2,M_3),\ (M_1,M_2,M_4)\ (M_1,M_2,M_5)(M_1,M_3,M_4)\ (M_1,M_3,M_5), \\ (M_1,M_4,M_5)\ (M_2,M_3,M_5) \ (M_2,M_4,M_5),(M_3,M_4,M_5) \ = \ 9$ $\to P(A \cap B)=\frac{9}{10}$

$= 0.9$

In point f:

$\to (A\cap B) = \frac{3}{10}$

$= 0.3$

In point g:

$\to (A \cup B) = \frac{7}{10}$

$=0.7$

In point h:

$\to p(A \cap B) = 0.3 \neq 0$

8 0

4 years ago

Chris is c yrs old .Tom is 5 years old younger than twice Chris's age .Write an expression to represent Tom's age?

Elodia [21]

5( 2 x c) i think that it would be

5 0

3 years ago

Read 2 more answers

Which is larger: <br> A. the absolute value of 12<br> B. the absolute value of -15

Minchanka [31]

Answer:

A

Step-by-step explanation:

I am pretty sure this is right and I hope this helps

8 0

3 years ago

Read 2 more answers

Determine the quadrant when the terminal side of the angle lies according to the following conditions: cos (t) < 0, csc (t) &

Bess [88]

Answer:

The angle is in the second quadrant.

Step-by-step explanation:

The cosecant of an angle is the same as the reciprocal of the sine of that angle. In other words, as long as $\sin (t) \ne 0$ ,

$\displaystyle \csc t = \frac{1}{\sin t}$ .

Therefore, $\csc(t) > 0$ is equivalent to $\sin (t) > 0$ .

Consider a unit circle centered at the origin. If the terminal side of angle $t$ intersects the unit circle at point $(x,\, y)$ , then

$\cos (t) = x$ , and
$\sin(t) = y$ .

For angle $t$ ,

$x = \cos(t) < 0$ , meaning that the intersection is to the left of the $y$ -axis.
$y = \sin(t) > 0$ , meaning that the intersection is above the $x$ -axis.

In other words, this intersection is above and to the left of the origin. That corresponds to second quadrant of the cartesian plane.

6 0

3 years ago