Answer:
<em>Vertex; ( - 1 / 2, 5 3/4 )</em>
Step-by-step explanation:
No need for a calculator, take a look at the procedure below;
The vertex of an up - down facing parabola of the form y = ax^2 + bx + c is x = -b / 2a;
The parabola params are given to be 1, 1, and 6, such that;
x = - 1 / 2 * 1,
x = - 1 / 2,
Now plug in this value of x into the quadratic function as to solve for y;
y = ( - 1 /2 )^2 - 1 /2 + 6,
y = 1 / 4 + 5 1 / 2,
y = 5 3/4
Thus the vertex has a minimum of ( - 1 / 2, 5 3/4 ),
<em>Vertex; ( - 1 / 2, 5 3/4 )</em>
