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adoni [48]
3 years ago
10

Find the nth term of 11, 21, 31, 41​

Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

nth term is (110)^n-1

Step-by-step explanation:

This is an arithmetic sequence so the explicit equation for that is

(a of n)= a1 * (r)^n-1

the nth term is (a of n)

(a of n)= 11* (10)^n-1

(a of n) = (110)^n-1

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The Gleason family has a monthly budget of $4,500. Mr. Gleason has a full-time job and takes home $900 each week. Mrs. Gleason w
lana [24]

Answer:

The value of x from the equation is 100. Thus, Mrs. Gleason should work for 100 hours per month. 

Step-by-step explanation:

To answer this item, we let x be the number of hours per month that Mrs. Gleason should work. The total budget is equal to sum of the amount acquired by Mr. Gleason and Mrs. Gleason. The equation that would express this is,

                         4,500 = 900(4) + 9x

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#18
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3 0
3 years ago
An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn, its color
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Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁          B₂B₁          W₁B₁          W₂B₁          W₃B₁

B₁B₂         B₂B₂          W₁B₂         W₂B₂          W₃B₂

B₁W₁         B₂W₁         W₁W₁         W₂W₁         W₃W₁

B₁W₂        B₂W₂         W₁W₂        W₂W₂         W₃W₂

B₁W₃        B₂W₃         W₁W₃        W₂W₃         W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36

Thus, the probability that only white balls are drawn is 0.36.

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