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katen-ka-za [31]
3 years ago
8

Help me fill in the blanks 6x + __ =3 (__ + 5)

Mathematics
1 answer:
Virty [35]3 years ago
4 0

Answer:

<u>15</u>

<u>2x</u>

Step-by-step explanation:

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A plumber charges $50 for a service call plus $80 per hour. If she spends no longer than 8 hours a day at any one site, find a l
Paha777 [63]

Answer:

C(t)=80t+50, \text{ for }t\leq 8.

Step-by-step explanation:

Let C represent total daily charges in dollars and t represent time in hours.

We have been given that a plumber charges $50 for a service call plus $80 per hour.  

The amount charged for t hours would be 80t.

The total amount charged for t hours would be C(t)=80t+50.

We are also told that plumber spends no longer than 8 hours a day at any one site, this means that time t have a restriction as:

t\leq 8

Therefore, our required cost function would be C(t)=80t+50, \text{ for }t\leq 8.

3 0
3 years ago
I need help! I'm *so* confused! I will mark Brainliest
Naddik [55]

Answer:

(-2,21)

Step-by-step explanation:

2 days ago, Paulo's commute time was halfway between his commute times 8 and 9 days ago.

8 days ago means that x-coordinate -8 represents this day. Count 8 units to the left and find that when x = -8, y = 24 minutes.

9 days ago means that x-coordinate -9 represents this day. Count 9 units to the left and find that when x = -9, y = 18 minutes.

Find halfway commute time between points (-8,24) and (-9,18):

y=\dfrac{24+18}{2}=\dfrac{42}{2}=21,

then coordinates that Paulo should graph are

(-2, 21)

(-2 means 2 days ago, 21 is the halfway)

5 0
3 years ago
The picture is there​
aliina [53]

Answer:

Step-by-step explanation:

Because CB = 6 cm, we can find CD

Use Triangle CDB.

<BCD = <BCA - <ACD

<BCD = ?

<BCA = 90

<ACD = 60

<BCD = 90 - 60

<BCD = 30

Cos 30 = CD / CB

CD = Cos(30) * BC

CD = 5.196 cm

<A = 90 - ACD

<ACD = 60

<A = 90 - 60

<A = 30

Sin(<A) = CB / AB

AB = CB / sin(<A)

AB = 6 / 0.5

AB = 12

Area =1/2 CD * AB

Area = 1/2 * 5.196 * 12

Area = 31.18

4 0
3 years ago
Pls help will be epik
DiKsa [7]
13 units.

Since both are negative, and they’re just asking for distance between, you can just subtract 12 from 25 to get 13.

5 0
2 years ago
I need help
agasfer [191]
(0,4) hope this helps
7 0
3 years ago
Read 2 more answers
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