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antiseptic1488 [7]

3 years ago

6

What is the equation of the line shown in the graph below

1 answer:

Dmitry [639]3 years ago

5 0

Use y=m(x+b)

Answer: y=-2x+2

You might be interested in

If f(x) = 7x+6 and g(x)=8x-4 find f(g(-2))

sp2606 [1]

Answer:

$f(g(-2))=-134$

Step-by-step explanation:

So we have the two functions:

$f(x)=7x+6\text{ and } g(x)=8x-4$

And we want to find f(g(-2)).

First, let's find g(-2):

$g(-2)=8(-2)-4$

Multiply:

$g(-2)=-16-4$

Subtract:

$g(-2)=-20$

Now, substitute:

$f(g(-2))=f(-20)$

Now, find the value of f(-20):

$f(-20)=7(-20)+6$

Multiply:

$f(-20)=-140+6$

Add:

$f(-20)=-134$

So:

$f(g(-2))=-134$

And we're done!

5 0

3 years ago

Which statement is true of triangles FGH and JKL?

Mars2501 [29]

Answer:

They are similar because their corresponding angles are congruent and their corresponding sides are proportional in length.

Step-by-step explanation:

From the statements,

∠G≅∠K

∠F≅∠J

∠H≅∠L

The sides of triangle FGH are proportional to those of triangle JKL

FG/JK =GH/KL=FH/JL =1/2

6 0

3 years ago

Read 2 more answers

Two-fifths of police officers New York police department are female

Over [174]

Answer:

$\\ \\ 3)15($

8 0

2 years ago

The numbers 1 through 15 are written on cards. One card is chosen at random. Event A is choosing a

lana [24]

Step-by-step explanation:

the probability is always the number of desired cases over the number of all possible cases.

in our situation we have 15 cards.

that is the total possible cases when a random card is chosen.

how many desired cases do we have ?

a number NOT a multiple of 5.

how many are there ?

it is easier to say how many numbers there are being a multiple of 5 : 5, 10, 15

so, 3 numbers out of the 15 are multiple of 5.

that means

15 - 3 = 12 numbers of the 15 are NOT multiples of 5.

so, the probability to draw a card that is not a multiple of 5 is

12/15 = 4/5 = 0.8

the information about event B and even numbers is irrelevant for the question.

6 0

2 years ago

A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t

VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field= $1500000$ square ft

Area of rectangular field= $l\times b$

Area of rectangular field= $x\time y$

$1500000=xy$

$y=\frac{1500000}{x}$

Fencing used ,P(x)= $x+x+y+y+y=2x+3y$

Substitute the value of y

P(x)= $2x+3(\frac{1500000}{x})$

$P(x)=2x+\frac{4500000}{x}$

Differentiate w.r.t x

$P'(x)=2-\frac{4500000}{x^2}$

Using formula: $\frac{dx^n}{dx}=nx^{n-1}$

$P'(x)=0$

$2-\frac{4500000}{x^2}=0$

$\frac{4500000}{x^2}=2$

$x^2=\frac{4500000}{2}=2250000$

$x=\sqrt{2250000}=1500$

It is always positive because length is always positive.

Again differentiate w.r.t x

$P''(x)=\frac{9000000}{x^3}$

Substitute x=1500

$P''(1500)=\frac{9000000}{(1500)^3}>0$

Hence, fencing is minimum at x=1 500

Substitute x=1 500

$y=\frac{1500000}{1500}=1000$

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used= $2(1500)+3(1000)=6000 ft$

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0

3 years ago