Which statement correctly compares the centers of the distributions?

there are 798 calories in six 10-ounce bottles of apple juice how many calories are there in one 10-ounce bottle of apple juice

bulgar [2K]

798 calories are in 6 10-ounce bottles of Apple juice. We have to calculate how many calories are in one 10-ounce bottle of Apple juice. We have just to divide 798 calories by 6: 798 : 6 = 133. Answer: There are 133 calories in one 10-ounce bottle of Apple juice

7 0

3 years ago

Drag each graph to show if the system of linear equations it represents will have no

Annette [7]

Top left, none
middle, many
top right, one
bottom left, none

if you extend the top and bottom left graphs, they won’t intercept. but if u extend the middle graph, they always intercept. and the top right graph only intercepts once

4 0

3 years ago

How much will $4.00 plus a 6% tax ?

blsea [12.9K]

The answer would be $4.24

6 0

3 years ago

Read 2 more answers

A company with a large fleet of cars wants to study the gasoline usage. They check the gasoline usage for 50 company trips chose

Nookie1986 [14]

Answer:

The 95% confidence interval is given by (25.71536 ;28.32464)

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)

Step-by-step explanation:

Notation and definitions

n=50 represent the sample size

$\bar X= 27.2$ represent the sample mean

$s=5.83$ represent the sample standard deviation

m represent the margin of error

Confidence =88% or 0.88

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Calculate the critical value tc

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 88% of confidence, our significance level would be given by $\alpha=1-0.88=0.12$ and $\alpha/2 =0.06$ . The degrees of freedom are given by:

$df=n-1=50-1=49$

We can find the critical values in R using the following formulas:

qt(0.06,49)

[1] -1.582366

qt(1-0.06,49)

[1] 1.582366

The critical value $tc=\pm 1.582366$

Calculate the margin of error (m)

The margin of error for the sample mean is given by this formula:

$m=t_c \frac{s}{\sqrt{n}}$

$m=1.582366 \frac{5.83}{\sqrt{50}}=14.613$

With R we can do this:

m=1.582366*(5.83/sqrt(50))

m

[1] 1.304639

Calculate the confidence interval

The interval for the mean is given by this formula:

$\bar X \pm t_{c} \frac{s}{\sqrt{n}}$

And calculating the limits we got:

$27.02 - 1.582366 \frac{5.83}{\sqrt{50}}=25.715$

$27.02 + 1.582366 \frac{5.83}{\sqrt{50}}=28.325$

Using R the code is:

lower=27.02-m;lower

[1] 25.71536

upper=27.02+m;upper

[1] 28.32464

The 95% confidence interval is given by (25.71536 ;28.32464)

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)

6 0

3 years ago

A refrigeration company held a 2-hour training program for 5 employees. The employees were all paid their regular wages for the

Svetradugi [14.3K]

The solution to the question how much was the total cost for the seminar is shown below:

Cost 1 = $ 340 for the total wages for the group
cost 2 =$5 x 5 employees, this is for the refreshments
cost 3 = $75 for the instructors fee
cost 4 = $250 for the supplies and others

Total cost = cost1 +cost2 +cost3 + cost 4
Total cost = $340 + ($5*5) + $75 + 250
Total cost = $690

3 0

3 years ago