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Arada [10]
4 years ago
14

Someone please answer this thanks I’ll give brainly

Mathematics
2 answers:
rjkz [21]4 years ago
8 0

Answer:

i cant see it sorryy

Step-by-step explanation:

Butoxors [25]4 years ago
3 0

Answer: I’m pretty sure it’s B

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PLEASE HELP I HAVE LIMITED TIME!!
MakcuM [25]

Answer:

N: n = 5 sides

side length: a = 23.2 m

inradius: r = 15.966 m

circumradius: R = 19.7351 m

Area: A = 926.03 m2

perimeter: P = 116 m

interior angle: x = 108 °

exterior angle:  y = 72 °

Description:

We use the calculations on the shape 16 and 23.2. Side length is 23.2. Pi is 16. calculate the numbers and all the answers are added above.

Please mark brainliest

<em><u>Hope this helps.</u></em>

8 0
3 years ago
What do i have to look up to learn how to do this kind of trig. I went through kahn academy for trig but this stuff never came u
mariarad [96]

Answer:

  (e) √(x² -1)

Step-by-step explanation:

You can look up the Pythagorean theorem, and SOH CAH TOA.

__

<h3>Pythagorean theorem</h3>

This tells you the relations between the sides of a right triangle. For the purpose of finding tan(θ), you need to know the length of the side that is not marked on the diagram. It is found using the Pythagorean theorem.

The sum of squares of the legs is equal to the square of the hypotenuse. If we call the unknown leg "o", then ...

  1² +o² = x² . . . . . the Pythagorean relation

  o² = x² -1 . . . . . . subtract 1

  o = √(x² -1) . . . . take the square root

__

<h3>SOH CAH TOA</h3>

This mnemonic reminds you of the relationship between trig functions and side lengths of a right triangle.

  • Sin = Opposite/Hypotenuse
  • Cos = Adjacent/Hypotenuse
  • Tan = Opposite/Adjacent

This tells you that tan(θ) is the ratio of the side opposite θ to the side adjacent:

  tan(θ) = o/1 = o

From the previous section, o = √(x²-1), so ...

  tan(θ) = √(x² -1) . . . . . . . matches choice (e)

_____

<em>Additional comment</em>

Another way to think about this is in terms of the trig identities you have learned:

  sec(θ) = 1/cos(θ) = 1/(1/x) = x

  sec²(θ) = tan²(θ) +1   ⇒   tan(θ) = √(sec²(θ) -1) = √(x² -1)

7 0
2 years ago
Which is the correct calculation for the volume of the prism?
Rom4ik [11]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Consider an unreliable communication channel that can successfully send a message with probability 1/2, or otherwise, the messag
Anon25 [30]

Answer:

6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

Step-by-step explanation:

Consider the provided information.

Let x is the number of times massage received.

It is given that the probability of successfully is 1/2.

Thus p = 1/2 and q = 1/2

We want the number of times do we need to transmit the message over this unreliable channel so that with probability 63/64 the message is received at least once.

According to the binomial distribution:

P(X=x)=\frac{n!}{r!(n-r)!}p^rq^{n-r}

We want message is received at least once. This can be written as:

P(X\geq 1)=1-P(x=0)

The probability of at least once is given as 63/64 we need to find the number of times we need to send the massage.

\frac{63}{64}=1-\frac{n!}{0!(n-0)!}\frac{1}{2}^0\frac{1}{2}^{n-0}

\frac{63}{64}=1-\frac{n!}{n!}\frac{1}{2}^{n}

\frac{63}{64}=1-\frac{1}{2}^{n}

\frac{1}{2}^{n}=1-\frac{63}{64}

\frac{1}{2}^{n}=\frac{1}{64}

By comparing the value number we find that the value of n should be 6.

Hence, 6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

7 0
3 years ago
What is 24x24x24? Please explain ;)
ANTONII [103]

{24}^{3 }  = 13824
Just multiply them 3 times. That's it
8 0
4 years ago
Read 2 more answers
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