Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
Answer:
okay thanks didn't expect this lol
Answer:
6B = F8
Step-by-step explanation:
I guess this will be good example of how to do it
Answer:
s ≤ -18
Step-by-step explanation:
Multiply both sides of the inequality by -3. Since the multiplier is negative, you need to reverse the comparison symbol.
(-3)(-s/3) ≤ (-3)(6)
s ≤ -18
_____
If you multiply by a positive number, you don't need to reverse the symbol. Hence multiplying by 3 gives ...
-s ≥ 18
You can now add s to both sides:
0 ≥ 18 + s
and subtract 18 from both sides:
-18 ≥ s
Of course, this is the same relationship as ...
s ≤ -18
