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3 years ago

Please Help Me!!!! Max Points

Mathematics

2 answers:

Arada [10]3 years ago

8 0

Answer:

P(5) = 1/3

Step-by-step explanation:

The probability of spinning a 5 = number of 5s / total number of spaces on the spinner. There is 1 5, and 3 numbers total, so

nordsb [41]3 years ago

6 0

Answer:

The probability of landing on 5 (P(5)) is 1/3

Step-by-step explanation:

The spinner is divided into three, so the probability of landing on five is 1 out of 3.

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Please help!! It’s an missing assignment due in 30 minutes these two are my last questions please!

LiRa [457]

There u go ur welcome!

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3 years ago

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What is an equation of the line that passes through the points (-2, 1) and (-8, 4)

telo118 [61]

Answer:

y= -1/2x

Step-by-step explanation:

y-y1/x-x1=y2-y1/x2-x1

y-1/x+2=-1/2

2y-2= -x-2

2y= -x-2+2

2y=-x

y=-1x/2„

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3 years ago

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A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

kherson [118]

Answer:

x = 0.53 cm

Maximum volume = 1.75 cm³

Step-by-step explanation:

Refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denote the length of the sides of the square as shown in the diagram.

The width of the shaded region is given by

$Width = 3 - 2x \\\\$

The length of the shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

In order to maximize the volume enclosed by the box, take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15) \\\\18x^2 -38x + 15 = 0 \\\\$

We are left with a quadratic equation.

We may solve the quadratic equation using quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Where

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$

Volume of the box at x= 1.59:

$V = \frac{1}{2} (5 – 3(1.59)) \times (3 - 2(1.59)) \times (1.59) \\\\V = -0.03 \: cm^3 \\\\$

Volume of the box at x= 0.53:

$V = \frac{1}{2} (5 – 3(0.53)) \times (3 - 2(0.53)) \times (0.53) \\\\V = 1.75 \: cm^3$

The volume of the box is maximized when x = 0.53 cm

Therefore,

x = 0.53 cm

Maximum volume = 1.75 cm³

7 0

3 years ago

if you practice a musical instrument each day for 2/3 of an hour how many hours of practice would you get in each week?

RideAnS [48]

In order to find the answer of the given problem above, we need to make the solution below:
Given: 2/3 of an hour = practice each day
2/3 of an hour is equivalent to 40 minutes
And per week, there are 7 days. So we will multiply 40 minutes by 7, and the result is 280 minutes. Since there are 60 minutes in an hour, we divide 280 by 60 and we get 4.67 hours. Therefore, each week, you would get 4.67 hours of practice on playing a musical instrument.

3 0

3 years ago

Evaluate: [(21 + 6) − 32] ÷ 9.2 A) 4. B) 4.6. C) 1. D) 52.

Dima020 [189]

[(21 + 6) - 32] : 9.2 = (27 - 32) : 9.2 = -5 : 9.2 = -46

5 0

3 years ago