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Mrac [35]
3 years ago
9

B Use your answer to write 48 cubed as a product of its prime factors in index form.

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0

Answer:

110592

Step-by-step explanation:

48x48x48

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Seema bought a new pair of jeans that were on sale. The original price of the jeans was $56. The store had marked them down by 2
Sav [38]

Answer:

C.) 33.60

Step-by-step explanation:

OMP. = $56

D. = 25%

0.25 * $56 = $14

SP. = $56-$14=$42

CD. = 20% of Selling price

= 0.20 * $42 = $8.40

FSP. = $42-$8.40      = $33.60

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6 0
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Step-by-step explanation:

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Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
mafiozo [28]

Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
If the circumference of a circle measures 5 pie cm, what is the area of the circle in terms of pie?
saw5 [17]

Answer:

6.25π cm²

Step-by-step explanation:

pi = π

Circumference = 5πcm

Now first we should find radius(r)

2πr = 5π cm

pie will be cancelled and we get here

r = 5/ 2 cm

Therefore r = 2.5 cm

Now

Area (A) = πr²

= π * 2.5²

= 6.25π cm²

4 0
3 years ago
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