Answer:
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A = base side=3
b= base side=5
c = base side=3
h= height=7-4=3
l= lenght=6
w= width=5
h= height=4
V= 1/4h√(-a⁴+2(ab)²+2(ac)²-b⁴+2(bc)²-c⁴) + l w h
V=12.44+ 120=132.44 unit³
Let
x---------> the length of the first piece
y---------> the length of the second piece
z---------> the length of the third piece
we know that
x+y+z=72 -------> equation 1
y=x+6 -----> solve for x
x=y-6 -------> equation 2
z=6+y -------> equation 3
substitute equation 2 and equation 3 in equation 1
[y-6]+y+[6+y]=72
3y=72
y=(72/3)=24 in
<u>Find the value of x</u>
x=y-6 -------> equation 2
x=24-6=18 in
<u>Find the value of z</u>
z=6+y -------> equation 3
z=6+24=30 in
therefore
<u>the answer is</u>
the length of the first piece is 18 in
the length of the second piece 24 in
the length of the third piece is 30 in
See attached picture for answre
