3 years ago

Can someone help me with these please

Mathematics

1 answer:

Savatey [412]3 years ago

4 0

Answer:

the answer is cubes curve

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Convert x2 + y2 -4x = 0 to polar form.

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$r(r-4\cos \theta)=0$

Step-by-step explanation:

We are given the following equation:

$x^2 + y^2 -4x = 0$

We have to convert it into polar form.

We put

$x = r \cos \theta\\y = r\sin \theta$

Putting values, we get:

$x^2 + y^2 -4x = 0\\(r\cos \theta)^2 + (r\sin \theta)^2 - 4(r\cos \theta) = 0\\r^2(\cos^2 \theta + \sin^2 \theta) - 4r\cos \theta = 0\\r^2 - 4r\cos \theta = 0\\r(r-4\cos \theta)=0$

is the required polar form.

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3 years ago