Answer:
x = 6
y = 2
Step-by-step explanation:
Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y))
∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y))
∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z)
∀x ∃z> V (x,y,z))
Answer:
This is actually not an identity.
n! is called a factorial.
It would look something like this: n! = 1·2·3·...·n
An example:
5! = 1·2·3·4·5 = 120
Answer:
9.14285714286
Step-by-step explanation:
i dont know if you need to round it but heres the answer (hasnt been rounded)