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earnstyle [38]
3 years ago
7

Which of the following z-scores indicates the most extreme observation?

Mathematics
1 answer:
UNO [17]3 years ago
5 0

Answer:

Step-by-step explanation:

Normally Z scores in a std normal distribution curve lie between -3 and 3 comprising more than 99% of total area.

Any entry outside (-3,3) can be considered as an extreme observation.

Here we have hence a) -4.3 is the most extreme observation.

-------------------------

Given that 84 separates the lowest 75% of the scores from the highest 25% of the scores,

This means 84 is the 75th percentile and similarly 65 is the 25th percentile.

Thus we have 84 has the percentile rank of 75

Option C

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Answer:

It's B, I'm only trying my best since there is no picture.

Step-by-step explanation:

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3 years ago
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How wold you put 4/1 as a fraction?
valentinak56 [21]
4/1 is 4. It's the same as saying 4 divided by 1

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two trains leave the station on time.one train travels north at 60mph .the other train travels south at 50mph.how many miles wil
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3 years ago
Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2
iren2701 [21]
Hello there, hope I can help!

I assume you mean L\left\{\frac{ekt+e-kt}{2}\right\}
With that, let's begin

\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \  L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}

\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}
\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b
L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}
\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}

L\left\{t\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \  L\left\{t\right\}=\frac{1}{s^2}

L\left\{\frac{e}{2}\right\} \ \textgreater \  \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \  L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \  \frac{e}{2s}

\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}

\frac{ek}{2}\cdot \frac{1}{s^2}  \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{ek\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{ek}{2s^2}

\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \  \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \  \frac{k\cdot \:1}{2s^2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{k}{2s^2}

\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}

Hope this helps!
3 0
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multiple means the product of each factor

so the multiples of 4 would be 4 8 12 16 20

you want to name at least five multiples but if there are not the same multiples you might have to list more

the multiples of 5 would be 5 10 15 20

then I can stop there because I have found two of the same multiples

so now we have our least common denominator which is 20

HOPE THIS HELPS!!!
6 0
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