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crimeas [40]
3 years ago
8

Determine the intercepts of the line 4x-3y=17

Mathematics
1 answer:
bezimeni [28]3 years ago
3 0

Answer:

x-intercept = 17/4 and y = -17/3

Step-by-step explanation:

To find the intercepts: set x = 0 for the y-intercept and solve the equation and set y =0 for the x- intercept and solve the equation.

To

4x - 3y = 17

4(0) - 3y = 17

0 - 3y = 17

  y = 17 /-3

 y = -17/3 = -5 2/3       y-intercept = -5 2/3.

The ordered pair on the graph is (0, -17/3)

   4x - 3(0) = 17

     4x - 0 = 17

      4x = 17

       x = 17/4       x-intercept = 17/4

    The ordered pair on the graph is (17/4, 0)

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X/-5=-20<br><br> A -100 or 100<br> B -4 or 4<br> C 100<br> D no solution
alexgriva [62]

Move the negative sign to the left

-x/5 = -20

Multiply both sides by 5

-x = -20 × 5

Simplify 20 × 5 to 100

-x = -100

Multiply both sides by -1

<em>x = 100</em>

<u>C. 100</u>

4 0
3 years ago
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Step-by-step explanation:

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3 years ago
Angela’s car leaked 6 ounces of oil in 9 days.what is the unit rate of the oil leak?
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5 0
3 years ago
Please help me ASAP! Triangle ABC is located at A (2, 3), B (4, 4), and C (6, 3). Zackary says that triangle ABC is an isosceles
son4ous [18]
<h2>Hello!</h2>

The answer is:

The second option,

Zackery, because AB=BC

<h2>Why?</h2>

To identify which type of triangle is the triangle formed by the given points, first, we need to calculate the distance between the points.

So, finding the distances we have:

From A to B: (2,3) and (4,4)

distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(4-2)^{2} +(4-3)^{2}}=\sqrt{2^{2} +1^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units

From B to C: (4,4) and (6,3)

distance=\sqrt{(x_2-x_1)^{2} +(y_2-y_1)^{2}}\\\\distance=\sqrt{(6-4)^{2} +(3-4)^{2}}=\sqrt{2^{2} +(-1)^{2} }=\sqrt{4+1}=\sqrt{5}=2.24units

Hence, since the distances AB and BC are equal, the triangle is an isosceles triangle, so the answer is:

Zackery, because AB=BC

Have a nice day!

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3 years ago
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Oksana_A [137]
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