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Ilia_Sergeevich [38]
3 years ago
7

-10 + (-3/4) PLEASE I NEED HELPP! ITS FOR A GRADE

Mathematics
2 answers:
Svetllana [295]3 years ago
6 0

Answer:

-10.74

Step-by-step explanation:

Cloud [144]3 years ago
4 0

Answer:

-\frac{43}{4} or -10.75 or -10\frac{3}{4}

Step-by-step explanation:

I assume you just wanted to add -10 and -\frac{3}{4}  together here.

The answers are as listed. If you need steps let me know.

<u>Hope this helps and have a nice day!</u>

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What do the medians and ranges of two dot plots tell you about the data
Tatiana [17]
That both (along with the mean) help the data be described the data's spread, which can be the slope if only two points.
5 0
3 years ago
Find all the complex roots. Write the answer in exponential form.
dezoksy [38]

We have to calculate the fourth roots of this complex number:

z=9+9\sqrt[]{3}i

We start by writing this number in exponential form:

\begin{gathered} r=\sqrt[]{9^2+(9\sqrt[]{3})^2} \\ r=\sqrt[]{81+81\cdot3} \\ r=\sqrt[]{81+243} \\ r=\sqrt[]{324} \\ r=18 \end{gathered}\theta=\arctan (\frac{9\sqrt[]{3}}{9})=\arctan (\sqrt[]{3})=\frac{\pi}{3}

Then, the exponential form is:

z=18e^{\frac{\pi}{3}i}

The formula for the roots of a complex number can be written (in polar form) as:

z^{\frac{1}{n}}=r^{\frac{1}{n}}\cdot\lbrack\cos (\frac{\theta+2\pi k}{n})+i\cdot\sin (\frac{\theta+2\pi k}{n})\rbrack\text{ for }k=0,1,\ldots,n-1

Then, for a fourth root, we will have n = 4 and k = 0, 1, 2 and 3.

To simplify the calculations, we start by calculating the fourth root of r:

r^{\frac{1}{4}}=18^{\frac{1}{4}}=\sqrt[4]{18}

<em>NOTE: It can not be simplified anymore, so we will leave it like this.</em>

Then, we calculate the arguments of the trigonometric functions:

\frac{\theta+2\pi k}{n}=\frac{\frac{\pi}{2}+2\pi k}{4}=\frac{\pi}{8}+\frac{\pi}{2}k=\pi(\frac{1}{8}+\frac{k}{2})

We can now calculate for each value of k:

\begin{gathered} k=0\colon \\ z_0=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{0}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{0}{2}))) \\ z_0=\sqrt[4]{18}\cdot(\cos (\frac{\pi}{8})+i\cdot\sin (\frac{\pi}{8}) \\ z_0=\sqrt[4]{18}\cdot e^{i\frac{\pi}{8}} \end{gathered}\begin{gathered} k=1\colon \\ z_1=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{1}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{1}{2}))) \\ z_1=\sqrt[4]{18}\cdot(\cos (\frac{5\pi}{8})+i\cdot\sin (\frac{5\pi}{8})) \\ z_1=\sqrt[4]{18}e^{i\frac{5\pi}{8}} \end{gathered}\begin{gathered} k=2\colon \\ z_2=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{2}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{2}{2}))) \\ z_2=\sqrt[4]{18}\cdot(\cos (\frac{9\pi}{8})+i\cdot\sin (\frac{9\pi}{8})) \\ z_2=\sqrt[4]{18}e^{i\frac{9\pi}{8}} \end{gathered}\begin{gathered} k=3\colon \\ z_3=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{3}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{3}{2}))) \\ z_3=\sqrt[4]{18}\cdot(\cos (\frac{13\pi}{8})+i\cdot\sin (\frac{13\pi}{8})) \\ z_3=\sqrt[4]{18}e^{i\frac{13\pi}{8}} \end{gathered}

Answer:

The four roots in exponential form are

z0 = 18^(1/4)*e^(i*π/8)

z1 = 18^(1/4)*e^(i*5π/8)

z2 = 18^(1/4)*e^(i*9π/8)

z3 = 18^(1/4)*e^(i*13π/8)

5 0
1 year ago
(x-2) Divided By (x^3-4x^2+ 6x-4) long divison
gayaneshka [121]
<span> x2 - 2x + 2
hope this helps</span>
8 0
4 years ago
Frieda is 67 inches tall and weighs 135 pounds. women her age have a mean height of 65 inches with a standard deviation of 2.5 i
blsea [12.9K]
<span>Frieda's weight is 1 Standard Deviation above the meanwhile her height is less than 1 Standard Deviation away from the mean. This means her height is closer to the mean than her weight.
As a result, we would say that her weight is definitely more unusual than her height because her weight is more standard deviations away from the mean.

Therefore,
</span><span>in relative terms, it is correct to say that:</span> Frieda's height is more unusual than her weight.
5 0
3 years ago
Please help, and plz don't be saying this is the right answer if u dont know for sure.
zepelin [54]

Answer:

135 degrees

Step-by-step explanation:

(8x-7)+(12x+57)=180

combine like terms

20x+50 = 180

subtract 50 on both sides

20x = 130

divide by 20

x = 130/20

x = 13/2

x = 6.5

cpq = 12x+57

cpq = 78 + 57

cpq = 135

4 0
3 years ago
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