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3 years ago

-10 + (-3/4) PLEASE I NEED HELPP! ITS FOR A GRADE

Mathematics

2 answers:

Svetllana [295]3 years ago

6 0

Answer:

-10.74

Step-by-step explanation:

Cloud [144]3 years ago

4 0

Answer:

$-\frac{43}{4}$ or -10.75 or -10 $\frac{3}{4}$

Step-by-step explanation:

I assume you just wanted to add -10 and $-\frac{3}{4}$ together here.

The answers are as listed. If you need steps let me know.

Hope this helps and have a nice day!

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What do the medians and ranges of two dot plots tell you about the data

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That both (along with the mean) help the data be described the data's spread, which can be the slope if only two points.

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3 years ago

Find all the complex roots. Write the answer in exponential form.

dezoksy [38]

We have to calculate the fourth roots of this complex number:

$z=9+9\sqrt[]{3}i$

We start by writing this number in exponential form:

$\begin{gathered} r=\sqrt[]{9^2+(9\sqrt[]{3})^2} \\ r=\sqrt[]{81+81\cdot3} \\ r=\sqrt[]{81+243} \\ r=\sqrt[]{324} \\ r=18 \end{gathered}$ $\theta=\arctan (\frac{9\sqrt[]{3}}{9})=\arctan (\sqrt[]{3})=\frac{\pi}{3}$

Then, the exponential form is:

$z=18e^{\frac{\pi}{3}i}$

The formula for the roots of a complex number can be written (in polar form) as:

$z^{\frac{1}{n}}=r^{\frac{1}{n}}\cdot\lbrack\cos (\frac{\theta+2\pi k}{n})+i\cdot\sin (\frac{\theta+2\pi k}{n})\rbrack\text{ for }k=0,1,\ldots,n-1$

Then, for a fourth root, we will have n = 4 and k = 0, 1, 2 and 3.

To simplify the calculations, we start by calculating the fourth root of r:

$r^{\frac{1}{4}}=18^{\frac{1}{4}}=\sqrt[4]{18}$

NOTE: It can not be simplified anymore, so we will leave it like this.

Then, we calculate the arguments of the trigonometric functions:

$\frac{\theta+2\pi k}{n}=\frac{\frac{\pi}{2}+2\pi k}{4}=\frac{\pi}{8}+\frac{\pi}{2}k=\pi(\frac{1}{8}+\frac{k}{2})$

We can now calculate for each value of k:

$\begin{gathered} k=0\colon \\ z_0=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{0}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{0}{2}))) \\ z_0=\sqrt[4]{18}\cdot(\cos (\frac{\pi}{8})+i\cdot\sin (\frac{\pi}{8}) \\ z_0=\sqrt[4]{18}\cdot e^{i\frac{\pi}{8}} \end{gathered}$ $\begin{gathered} k=1\colon \\ z_1=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{1}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{1}{2}))) \\ z_1=\sqrt[4]{18}\cdot(\cos (\frac{5\pi}{8})+i\cdot\sin (\frac{5\pi}{8})) \\ z_1=\sqrt[4]{18}e^{i\frac{5\pi}{8}} \end{gathered}$ $\begin{gathered} k=2\colon \\ z_2=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{2}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{2}{2}))) \\ z_2=\sqrt[4]{18}\cdot(\cos (\frac{9\pi}{8})+i\cdot\sin (\frac{9\pi}{8})) \\ z_2=\sqrt[4]{18}e^{i\frac{9\pi}{8}} \end{gathered}$ $\begin{gathered} k=3\colon \\ z_3=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{3}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{3}{2}))) \\ z_3=\sqrt[4]{18}\cdot(\cos (\frac{13\pi}{8})+i\cdot\sin (\frac{13\pi}{8})) \\ z_3=\sqrt[4]{18}e^{i\frac{13\pi}{8}} \end{gathered}$

Answer:

The four roots in exponential form are

z0 = 18^(1/4)*e^(i*π/8)

z1 = 18^(1/4)*e^(i*5π/8)

z2 = 18^(1/4)*e^(i*9π/8)

z3 = 18^(1/4)*e^(i*13π/8)

5 0

1 year ago

(x-2) Divided By (x^3-4x^2+ 6x-4) long divison

gayaneshka [121]

x2 - 2x + 2
hope this helps

8 0

4 years ago

Frieda is 67 inches tall and weighs 135 pounds. women her age have a mean height of 65 inches with a standard deviation of 2.5 i

blsea [12.9K]

Frieda's weight is 1 Standard Deviation above the meanwhile her height is less than 1 Standard Deviation away from the mean. This means her height is closer to the mean than her weight.
As a result, we would say that her weight is definitely more unusual than her height because her weight is more standard deviations away from the mean.

Therefore,
in relative terms, it is correct to say that: Frieda's height is more unusual than her weight.

5 0

3 years ago

Please help, and plz don't be saying this is the right answer if u dont know for sure.

zepelin [54]

Answer:

135 degrees

Step-by-step explanation:

(8x-7)+(12x+57)=180

combine like terms

20x+50 = 180

subtract 50 on both sides

20x = 130

divide by 20

x = 130/20

x = 13/2

x = 6.5

cpq = 12x+57

cpq = 78 + 57

cpq = 135

4 0

3 years ago