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Jobisdone [24]
2 years ago
8

Please help me please Dont Spam!!​

Mathematics
1 answer:
yaroslaw [1]2 years ago
4 0

Answer:

Please help me please Dont Spam!!​

Step-by-step explanation:

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Please help me out on here! Will give brainlest
laiz [17]

Answer:

7)

Step-by-step explanation:

The pattern is: add two more than you did before: starting from 2.

It would be:

1, 3, 7, 13,  21,  31, 43, 57

+2 +4 +6 +8 +10  +12  +14

Now use this to answer the questions.

Hope this helped!

Have a nice day!

(it would be nice if you gave me brainliest)

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6 0
3 years ago
A line passes through the point (10,-8) and has a slope of negative 3/2Write an equation in slope-intercept form for this line.
zhuklara [117]

Answer:

9383

Step-by-step explanation:

4 0
3 years ago
I need answers ASAP<br>​
AURORKA [14]

Answer:

Simplifying

6r + r + -5r = 0

Combine like terms: 6r + r = 7r

7r + -5r = 0

Combine like terms: 7r + -5r = 2r

2r = 0

Solving

2r = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Divide each side by '2'.

r = 0

Simplifying

r = 0

8 0
3 years ago
Read 2 more answers
Solve the following equation by completing the square. 12x^2 - 48x = -39​
daser333 [38]

Answer:

\large\boxed{\boxed{x = \begin{cases} \frac{ \sqrt{3} }{2}  + 2 \\     - \frac{ \sqrt{3} }{2}  + 2 \end{cases}}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic equation
  • PEMDAS
<h3>let's solve:</h3>
  1. \sf divide \: both \: sides \: by \: 12 :  \\  \sf  {x}^{2}  - 4x =  -  \frac{13}{4}
  2. \sf \: add  \: { -  2}^{2}  \: to \: both  \: sides :  \\  \sf  { {x}^{2} } - 4x + ( -  {2}^{2} ) =  \frac{13}{4}  + (  { - 2}^{2} ) \\  {x}^{2}  - 4x  + 4 =  \frac{13}{4}  + 4
  3. \sf simplify \: addition :  \\  \sf  { {x}^{2} } - 4x + 4 =  \frac{3}{4}
  4. \sf use \:  {a}^{2}  - 2ab +  {b}^{2}  = (a - b {)}^{2}  :  \\  \sf (x - 2 {)}^{2}  =  \frac{3}{4}
  5. \sf squre \: root \: both \: sides :  \\  \sf  \sqrt{(x - 2 {)}^{2} }  =  \pm \sqrt{ \frac{3}{4} }  \\ \begin{cases} x  - 2 =  \frac{ \sqrt{3} }{2}  \\x - 2 =  -  \frac{ \sqrt{3} }{2}  \end{cases}
  6. \sf add  \: 2 \: to \: both \: sides :  \\  \sf  \begin{cases}x =  \frac{ \sqrt{3} }{2}  + 2 \\  x =   - \frac{ \sqrt{3} }{2}  + 2 \end{cases} \\  \therefore \: x =  \begin{cases} \frac{ \sqrt{3} }{2}  + 2 \\     - \frac{ \sqrt{3} }{2}  + 2 \end{cases}
7 0
3 years ago
Read 2 more answers
Ahh I need help with this
sergiy2304 [10]

Answer:

i thinkbit is C but im in 6th grade and at may 5 i. not there yet

4 0
3 years ago
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