We have by distributivity of limits over sums, and continuity of 
and 
, that
Given 
, it follows that
Answer:
x = 4 , y = 1
Step-by-step explanation:
3x + 2y = 14 → (1)
x + y = 5 → (2)
Multiplying (2) by - 2 and adding to (1) will eliminate the y- term
- 2x - 2y = - 10 → (3)
Add (1) and (3) term by term to eliminate y
x = 4
Substitute x = 4 into (2) and evaluate for y
4 + y = 5 ( subtract 4 from both sides )
y = 1
The first graph is what i would think
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