Stop by the side of the road and call someone you know with a tire or call a tire shop but you'll have to pay extra
Answer:
The algorithm is as follows;
1. Start
2. Input TeddyBears
3. Input Hours
4. WagebyTeddy = 2 * TeddyBears
5. WagebyHour = 5 * Hours
6. If WagebyHour > WagebyTeddy then
6.1 Print WagebyHour
7. Else
7.1. Print WagebyTeddy
8. Stop
Explanation:
The following variables are used;
TeddyBears -> Number of teddy bears made
Hours -> Number of Hours worked
WagebyTeddy -> Wages for the number of teddy bears made
WagebyHour -> Wages for the number of hours worked
The algorithm starts by accepting input for the number of teddy bears and hours worked from the user on line 2 and line 3
The wages for the number of teddy bears made is calculated on line 4
The wages for the number of hours worked is calculated on line 5
Line 6 checks if wages for the number of hours is greated than wages for the number of bears made;
If yes, the calculated wages by hour is displayed
Otherwise
the calculated wages by teddy bears made is displayed
<span>This problem is an
example of ratio and proportion. You are given 6y:9y. You are required to
convert this into its simplest form. The 6y:9y is also equivalent to 6y/9y. The
‘y’ variable can be eliminated since it has the same exponent and base. You are
left with 6/9. The common factor for 6 and 9 is 3 so divide each number by 3. So
6/3 is 2 and 9/3 is 3. You get 2/3. This is its simplest form.</span>
Answer:
B
Explanation:
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