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galben [10]
3 years ago
5

Hanging out with friends, watching your favorite TV show, and buying a pair of new shoes are all examples of _____ for doing wel

l in school.
Computers and Technology
2 answers:
SpyIntel [72]3 years ago
8 0
<span>Hanging out with friends, watching your favorite TV show, and buying a pair of new shoes are all examples of rewards for doing well in school. As the result of doing well in studies, a person can hang out with friends, watch their own favorite TV show and can buy a new pair of shoes. Hence all these things are the rewards that are being generated for a good performance in school.</span>
Nikitich [7]3 years ago
8 0
Correct answer is rewards
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Name two components required for wireless networking<br>(answer fastly)​
Luden [163]

Explanation:

User Devices. Users of wireless LANs operate a multitude of devices, such as PCs, laptops, and PDAs. ...

Radio NICs. A major part of a wireless LAN includes a radio NIC that operates within the computer device and provides wireless connectivity.

or routers, repeaters, and access points

5 0
2 years ago
Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

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3 years ago
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3 years ago
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The inflationary gap occurs when you obtain no increase in output, but only an increase in the Average Price Level from an incre
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3 years ago
All the read/write heads a hard disk are controlled by a(n) ____ which moves the read/write heads across the disk surfaces in un
Maru [420]

Answer:  b. actuator

Explanation:

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[An actuator is a part of a device that is mainly responsible for moving and controlling a mechanism or system.]

Hence, All the read/write heads a hard disk are controlled by an actuator .

5 0
2 years ago
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