Question

How do I find the area of these?

Answer 1

Answer:

For b. 11*3x = 33x

For c. (3x-4)(11x-2) = $33x^{2} -50x+8$

Explanation:

For b. Since it is a rectangular the A = l*w

w = 11 & l = 3x => A = 11*3x = 33x

For c. Since it is a square we could assume that the A =$s^{2}$ a side squared  (since they all have the same length) but to be on the safe side, we'll assume it is not a square and do the math of multiplying one side by another (just like for a rectangle)

Side up = 3x + (-4) = 3x-4

Side left = 11x + (-2) = 11x-2

Side up * Side left = (3x-4)(11x-2) = $33x^{2} -50x+8$