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choli [55]
3 years ago
10

13. The length of a rectangle is 9 cm more than 2 times the width. If the perimeter of the rectangle is 60 cm,

Mathematics
1 answer:
tigry1 [53]3 years ago
8 0
A


Mark brainliest please


Hope this helps you
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Write the vertex form equation for this parabola: Focus (3,-9), Directrix X=-3
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5.63 + 14.37 PLZ ANSWER QUICK
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To add decimals, line up the decimal points.
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5 0
3 years ago
A recent study reported that diastolic blood pressures of adult women in the United States are approximately normally distribute
Zina [86]

Answer:

Proportion of women having blood pressures between 88.1 and 89.4 is 3.99% or close to 4%.

Step-by-step explanation:

We are given that a recent study reported that diastolic blood pressures of adult women in the United States are approximately normally distributed with mean 80.3 and standard deviation 8.6.

Let X = blood pressures of adult women in the United States

So, X ~ N(\mu=80.3,\sigma^{2} =8.6^{2})

The z score probability distribution is given by;

              Z = \frac{X-\mu}{\sigma} ~ N(0,1)  

where, \mu = population mean

           \sigma = population standard deviation

So, Probability that women have blood pressures between 88.1 and 89.4 is given by = P(88.1 < X < 89.4) = P(X < 89.4) - P(X \leq 88.1)

   P(X < 89.4) = P( \frac{X-\mu}{\sigma} < \frac{89.4-80.3}{8.6} ) = P(Z < 1.05) = 0.85314

   P(X \leq 88.1) = P( \frac{X-\mu}{\sigma} \leq \frac{88.1-80.3}{8.6} ) = P(Z \leq 0.89) = 0.81327

Therefore, P(88.1 < X < 89.4) = 0.85314 - 0.81327 = 0.0399 or approx 4%

Hence, proportion of women have blood pressures between 88.1 and 89.4 is 4%.

7 0
4 years ago
What is the nearest whole number to 53.67
Svetradugi [14.3K]
53.67 will round to 54
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