Step-by-step explanation:
again, 2 unknowns.
x = number of 2- points baskets
y = number of 3- points baskets
we know they hit the basket 37 times in a so far unknown mixture of 2-point and 3- point throws.
x + y = 37
which gives us e.g.
x = 37 - y
and we know that with this unknown mixture they scored 80 points.
so,
2x + 3y = 80
as every successful 2-points throw scores 2 points, and every successful 3-points throw scores 3 points.
so, again our 2 equations :
x = 37 - y
2x + 3y = 80
remember, we prepared the first equation so that it gives us already an identity expressing one variable by the other. and that we use in the second equation :
2×(37 - y) + 3y = 80
74 - 2y + 3y = 80
74 + y = 80
y = 6
and from
x = 37 - y
we get
x = 37 - 6 = 31
so, they had 31 2-points throws and 6 3-points throws.
Answer:
13 pounds
Step-by-step explanation:
205-192=13
"Contains four right angles" is the one among the following choices given in the question that is <span>not a property of a parallelogram. Parallelograms can have angles that are not ninety degrees. The correct option among all the options that are given in the question is the second option or option "B". </span>
First, you must find the width of GHJK. Since the area of it is 84m², divide 84 by 7.
84÷7=12
So the width of GHJK is 12m.
Next, find the scale of GHJK to LMNP. Since the height of both are already available, you can divide 21÷7 to get 3
This means that to get the width of LMNP you must multiply the width of GHJK by 3.
12×3=36.
Now, to get the area of LMNP, multiply 21 by 36.
21×36=756
So, the area of LMNP is 756m². (Don't forget the units!>
Answer:
The results don't make sense
Step-by-step explanation:
We can solve by means of a 2x2 system of equations, we have to:
"x" is the number of children's tickets
"y" is the number of adult tickets
Thus:
8 * x + 8.75 * y = 259
x + y = 35 => x = 35 - y
replacing we have:
8 * (35 - y) + 8.75 * y = 259
280 - 8 * y + 8.75 * y = 259
- 8 * y + 8.75 * y = 259 - 280
0.75 * y = -21
y = -21 / 0.75
y = -28
Thus:
x = 35 - (-28) = 63
With these results we notice that the problem has inconsistency, since the value of the tickets cannot be given a negative number, I recommend reviewing the problem, since the approach is correct.
