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pickupchik [31]
2 years ago
9

A teacher gives a 10-point to a class of 10 children.

Mathematics
1 answer:
natulia [17]2 years ago
7 0

Given what we know, we can say that it is possible for 9 out of 10 students to score above average, but it is not possible for all 10 to score above average.

<h3>How do we calculate an average score?</h3>

In order to calculate the average score of the students, we must use addition.

We have to add all of the scores, in this case, 10 scores, and then divide by the number of scores.

One example of 9 out of 10 students scoring above average would be:

1 + 9 +9+9+9+9+9+9+9+9 = 82

82/10 scores = 8.2

This would leave us with an average score of 8.2 and 9 out of 10 students that have scored higher.

Given the way in which we calculate average scores, it is impossible for all 10 students to score above average since even if all 10 students get a perfect score, that would then become the average.

To learn more about average calculations visit:

brainly.com/question/18554478?referrer=searchResults

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3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie
allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x  = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 53^\circ=\frac{150-x}{h}

\displaystyle \tan 48^\circ=\frac{x}{h}

From the last equation:

x=h.\tan 48^\circ

Substituting into the first equation:

\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}

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\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ

Rearranging:

\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}

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\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}

Calculating:

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