Answer:
Step-by-step explanation:
The 0 in the real number system goes into the most specific subset of real numbers we have, which is the whole numbers. Whole numbers include the 0, and next is the less specific natural or counting numbers which do not include the 0. (Next comes the integers and after that rational numbers, each getting less specific as they radiate out from the center)
-11 x² = x + 11
11 x² + x + 11 = 0
We will find the value of the discriminant:
D = b² - 4 a c = 1² - 4 * 11 * 11 * 1 - 484 = - 483
D < 0. There are no real solutions.
The slope is 3/5 just count the units up and to the side
Answer:
kjhgikoljuuihg
Step-by-step explanation:
bgkjm
Answer:
<em>The probability that the second ball is red is 71%</em>
Step-by-step explanation:
<u>Probabilities</u>
We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).
The first ball can be red (R) or green (G). The probability that it's red is computed by

The probability is's green is computed by

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

The total probability of the second ball being red is

The probability that the second ball is red is 71%