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svp [43]
2 years ago
14

The area of a rectangular wall of a barn is 33 square feet. Its length is 8 feet longer than the width. Find the length and widt

h of the wall of the barn.
Mathematics
1 answer:
Rama09 [41]2 years ago
4 0

Answer:

Width=3ft

Length=11ft

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9(4b-1)=2(b+3) Slove for b plz answer as quick as u can please
Jobisdone [24]

36b - 9 = 2b + 6 \\ 34b = 15 \\ b =  \frac{15}{34}
3 0
3 years ago
Solve this inequality for x. 81-1 1/5 x <55
katen-ka-za [31]

Answer:

A. x > 21 2/3

Step-by-step explanation:

x is greater than 21 and two thirds

i did the math :]

4 0
3 years ago
Use the diagram of the right triangle above and round your answer to the nearest hundredth.
Yakvenalex [24]
Answer: a = 23 ft.

Reasoning:

The question asks for the value of the leg a, given the tangent of the opposite angle and the length of the adjacent-leg, b.

The ratio that relates the three parameters is:

tan(A) = opposite-leg / adjacent-leg = a / b = a / 23 ft

Solve for a, wich is the unknown:

a = 23ft * tan(A) = 23ft * 1.0 = 23 ft

Answer: 23 ft.
7 0
3 years ago
There are many square prisms with volume 125 in. Let w represent the side length of the square base and h represent the height i
iogann1982 [59]

Answer:

5in by 5in by 5in

Step-by-step explanation:

We are not told wat to find but we can as well find the dimension of the prism that will minimize its surface area.

Given

Volume = 125in³

Formula

V = w²h ..... 1

S = 2w²+4wh ..... 2

w is the side length of the square base

h is the height of the prism

125 = w²h

h = 125/w² ..... 3

Substitute eqn 3 into 2 as shown

S = 2w²+4wh

S = 2w²+4w(125/w²)

S = 2w²+500/w

To minimize the surface area, dS/dw = 0

dS/dw =4w-500/w²

0= 4w-500/w²

Multiply through by w²

0 = 4w³-500

-4w³ = -500

w³ = 500/4

w³ =125

w = cuberoot(125)

w = 5in

Get the height

125 =w²h

125 = 25h

h = 125/25

h = 5in

Hence the dimension of the prism is 5in by 5in by 5in

5 0
3 years ago
The boxed definition of absolute value states that |a|=-a if a is a negative number. Explain why |a| is always nonnegative, even
Temka [501]

Final answer:

Since absolute values determine the distance between the number and the value whether the value is positive or negative. As distance is always positive.

Thus, |a| is always nonnegative, even though |a|=-a for negative values of a.

Step-by-step explanation:

Step 1

It is said that |a| is always nonnegative even though even though |a|=-a for negative values of a.

Step 2

This is because by the definition of an absolute value, any real number inside an absolute value symbol || will always be positive.

7 0
2 years ago
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