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andrezito [222]
3 years ago
5

A recursive arithmetic sequence is defined ad f(1)=6, f(n+1)=f(n)+5 for n>1. The first four terms of the sequence are shown i

n the table. Write an explicit formula that represents the sequence using function notation. Find the slope of the line that passes through the points given in the table. The slope is

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
7 0
Write the first few terms of the sequence.
f₁ = 6
f₂ = f₁ + 5 = 11
f₃ = f₂ + 5 = 16
f₄ = f₃ + 5 = 21
and so on

The sequence is
6, 11, 16, 21, ...,
This is an arithmetic sequence with a common difference of 5.

In function notation, the sequence is
f_{n+1} = 6 + 5n, \\ \, n=0,1,2, \, ...,

This represents the equation of a straight line with n as the independent variable and f as the dependent variable.
The slope is 5. 
A graph of the line is shown below.

Answer:
The sequence is f_{n+1} = 6 + 5n, \,\, n=0,1,2, \, ...,
The slope is 5.

MrMuchimi3 years ago
7 0

<u>Answer:</u>

Find the slope of the line that passes through the points given in the table. The slope is 5.

Use one of the given points to find the y-intercept. Substitute values for x, y, and m into the equation y = mx + b and solve for b. The y-intercept is 1.

Write the formula as a function of n in slope-intercept form. The function is f(n) = 5n + 1 for n in the set of natural numbers.

Your Welcome and don't forget to press that <u>Thanks</u> button :)

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If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f
poizon [28]

Answer:

The first occurence of t for which x = 0 is t = 0.5.

Step-by-step explanation:

The harmonic motion is described by the following equation.

x(t) = 3\cos{\pi t}

What is the first occurrence of a value of t for which x = 0?

This is t when x(t) = 0. So

x(t) = 3\cos{\pi t}

3\cos{\pi t} = 0

\cos{\pi t} = \frac{0}{3}

\cos{\pi t} = 0

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

\arccos{\cos{\pi t}} = \arccos{0}

\pi t = \frac{\pi}{2}

t = \frac{\pi}{2 \pi}

t = \frac{1}{2}

t = 0.5

The first occurence of t for which x = 0 is t = 0.5.

3 0
3 years ago
PLEASE HELPPP!!! Which expression is equivalent to sum of quantity negative three and one third times n plus one sixth end quant
uranmaximum [27]

The given expression is equivalent to the expression - 11/6 n - 1/12. Then the correct option is C.

<h3>What is Algebra?</h3>

The analysis of mathematical representations is algebra, and the handling of those symbols is logic.

The sum of capacity minus three and one-third times n plus one-sixth ended capacity + capacity one and three-sixths times n minus three-twelfths end quantity.

Let n be the number. Then the expression will be

⇒ -(3  1/3)n + 1/6 + (1  3/6)n - 3/12

Simplify the equation, then we have

⇒ -(3  1/3)n + 1/6 + (1  3/6)n - 3/12

⇒ -10/3 n + 3/2 n + 1/6 - 1/4

⇒ -11/6 n - 1/12

The given expression is equivalent to the expression - 11/6 n - 1/12. Then the correct option is C.

More about the Algebra link is given below.

brainly.com/question/953809

#SPJ1

8 0
1 year ago
Standard form Ax+By=C<br> x-3y=-6
Gennadij [26K]

Explanation:

The equation is already in standard form.

A is 1. The number 1 is often unwritten.

B is -3. The negative or positive sign is included with the equation.

C is -6. (If using this for the quadratic formula, c is actually 6 because the equation should equate to 0).

8 0
3 years ago
Slope intercept form
Liula [17]
\frac{y_{2}- y_{1}  }{x_{2}- x_{1}  }
8 0
3 years ago
Multiply and simplify the following complex numbers:<br> (-3 - 2i) x (-4 + 2i)
Alja [10]
(-3 - 2i) x (-4+ 2i) if you simplify using FOIL you will get 16+2i
5 0
3 years ago
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