3 boys + 8 girls = 11 students
3 boys/ 11 students = x boys /33 students
using cross products
3 * 33 = x*11
divide by 11
99/11 = x
x=9
There are 9 boys
Answer:
No.
Step-by-step explanation:
Since we know the side lengths of the triangle, we can figure out whether or not this is a Pythagorean triple.
Pythagorean theorem: a^2 + b^2 = c^2
a and b are both smaller than c.
So,
8^2 = 64.
13^2 = 169.
15^2 = 225.
64 + 169 = 233.
233 is not equal to 225.
Therefore, this is not a right triangle.
Step-by-step explanation:
H0: u = 44.3
Hi : u# 44.3
Z1-0.05/2
Z1-0.025
Z0.975 = 1.96
Z = x-u/s.d/√n
Z= 44.4 -44.3/2.6/√130
Z = (0.1×11.4018)/2.6
Z=0.44
Since the calcalculated value is less than the table value and does not fall in the rejection region we fail to reject the null hypothesis
Answer:
the answers are p - 6, 3 (1/3p + 3 - 5), and 3 (1/3p - 2)
It’s gonna be B coefficient