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Aleonysh [2.5K]
3 years ago
10

Hi, this is multiplication with decimals, help!

Mathematics
2 answers:
Greeley [361]3 years ago
7 0

Answer:

Sean paid 0.25 more cents than Cal.

Step-by-step explanation:

Cal's problem: 2.4 * 2.55 = 6.12

Sean's problem: 2.6 * 2.45 = 6.37

Ksenya-84 [330]3 years ago
4 0

Answer:

I think 0.25

Step-by-step explanation:

Multipled 2.4 and 2.55 then multipled 2.6 and 2.45. I got 6.12 and 6.37 Then subtracted them and got 0.25

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Leno4ka [110]
Use photo math to help you with this question
6 0
3 years ago
Answer this please ‍thank you uwuw
koban [17]

Answer:

27

divide 42 by 33 and multiply by 100 =127

8 0
3 years ago
Consider the following.
san4es73 [151]

Answer:

Anything in the form x = pi+k*pi, for any integer k

These are not removable discontinuities.

============================================================

Explanation:

Recall that tan(x) = sin(x)/cos(x).

The discontinuities occur whenever cos(x) is equal to zero.

Solving cos(x) = 0 will yield the locations when we have discontinuities.

This all applies to tan(x), but we want to work with tan(x/2) instead.

Simply replace x with x/2 and solve for x like so

cos(x/2) = 0

x/2 = arccos(0)

x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k

x = pi + 4pi*k   or    x = -pi + 4pi*k

Where k is any integer.

If we make a table of some example k values, then we'll find that we could get the following outputs:

  • x = -3pi
  • x = -pi
  • x = pi
  • x = 3pi
  • x = 5pi

and so on. These are the odd multiples of pi.

So we can effectively condense those x equations into the single equation x = pi+k*pi

That equation is the same as x = (k+1)pi

The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).

3 0
3 years ago
Help, WIll give 20 points
Kisachek [45]

Answer:

i dont know

Step-by-step explanation:

6 0
3 years ago
Can someone please help, ty!! <br> (Will mark brainliest)
Ahat [919]

Answer:

Its the second one

Step-by-step explanation:

I used slope to solve it

5 0
3 years ago
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