<em><u>The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:</u></em>
<em><u>Solution:</u></em>
<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the formula:</u></em>
To find the time interval in which the object is at a height greater than 300 ft
Frame a inequality,
Solve the inequality
Subtract 1000 from both sides
Time cannot be negative
Therefore,
t < 6.61
And the inequality used is: 
A. x=the cost of one lunch. 60.25=5x+3(x-5.25)
b. 60.25=5x+3x-15.75 60.25+15.75=8x-15.75+15.75
76=8x 76/8=8x/8 9.50=x
A lunch is $9.50. If you are not sure, check my answers. Hope this helped.
Answer:
If the darker, longer lines are going in units of one, then A is equal to -2.
Step-by-step explanation:
Answer:
a)
90% confidence interval for the mean grading time of all composition papers.
(12.47981 , 13.52019)
b)
Appropriate inequality
The interval is ( 12.47981 < μ < 13.52019)
Step-by-step explanation:
<u><em>Explanation</em></u>:-
a)
Given sample size 'n' = 40
Mean of the sample = 13 minutes
standard deviation = 2 min
level of significance = 0.10 or 90%
90% confidence interval for the mean grading time of all composition papers.
( 13 - 0.52019 , 13 + 0.52019)
(12.47981 , 13.52019)
b)
The interval is ( 12.47981 < μ < 13.52019)
