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3 years ago

7/10+2/5 please show work 30 POINTS

Mathematics

2 answers:

In-s [12.5K]3 years ago

6 0

Answer:

See Explanation

Step-by-step explanation:

LCD: Least Common Denominator.

Always remember that term when simplifying, multiplying, addidng, and dividing fractions with different denominators.

Numerator: Boring ter for top number

Denominator: Fancy term for bottom feeder. . . I mean, number.

7/10 + 2/5

To begin, you need to find how to make 2/5 equal ?/10. Why 10 as the denominator, you ask? Because LCD rule states you must find LOWEST COMMON MULTIPLE of the two denominators, which, in this case, happens to be 10! Lucky you.

SO, 7/10 + ?/10. . . now, how do you find the numerator (?)

Well, rules of math ALWAYS state what you do to ONE side must be replicated to the OTHER side, In this case, you changed 2/5 to ?/10, meaning you multiplied the 5 by TWO to get 10. This means you must multiply the 2 by TWO to answer the numerator!!

so, 2/5 now becomes 4/10.

Add!

7/10 + 4/10 = 11/10. This is known as an improper fraction. These guys have absolutely no manners or common decency to the math world. Make them PROPER by backslapping them into their place! Rather, into their whole & proper place, I should say.

11/10 is an improper fraction and can be transferred into 1 & 1/10

(When writing it, make the 1 REALLY big and the 1/10 REALLY small. This is because the 1 is a superior WHOLE number and the 1/10 is a measly fraction still. Respect.)

Hope this helps!

KengaRu [80]3 years ago

3 0

Answer:

11/10 or 1 1/10 or 1.1

Step-by-step explanation:

7/10+2/5

7/10+4/10 you want to make the denominator the same

11/10 now that the denominators are the same you can add the numerators

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Ratling [72]

Answer:

is equel to the same thing you just said twice lol

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3 years ago

Lines a and b are parallel. line c is perpendicular to both line a and line B. Which statement about lines a,b and C is not true

7nadin3 [17]

When lines are parallel, they have the same slope, so the statement "line a and line b have the same slope" is TRUE

When lines are perpendicular, the slopes are opposites (the sign and number is flipped)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -1

perpendicular line's slope is 1/1 or 1

slope is 4/5

perpendicular line's slope is -5/4

When you multiply(the product) perpendicular slopes together, they equal -1. Since line c is perpendicular to line a and line b, the product of their slopes is -1.(so this is true)

The statement "the sum of the slopes of line a and b is 0" is false because if they have the same slope, when added together the result would not be 0. The slopes of line a and line b is -2/3, so the sum would be -4/3.

7 0

3 years ago

Read 2 more answers

I learn maths and I don't know how to solve this problem.

Lyrx [107]

Answer:

As we get closer to x=-3, the limit is approaches -1, on both sides of -3 so this is a good limit so c is 8.

Step-by-step explanation:

In order for a limit to exists, the left side limit must exist and right side limit must exist and on top of that, they must be equal to each other.

In this case, this a piece wise function and by definition of a limit that exist, the limit of this piece wise function as x approaches 3 from either side, must be equal.

We let x=-3 for the top equation.

$( - 3) {}^{2} - 10 = - 1$

So we set the second equation equal to -1.

$- ( {x}^{2} ) + c = - 1$

$- ( - 3 {}^{2} ) + c = - 1$

$- 9 + c = - 1$

$c = 8$

So the value of c is 8. We can prove this by graphing as well.

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3 years ago

Differentiate with respect to x (6-2x)^3

olga55 [171]

-6(6-2x)^2 by chain rule

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2 years ago

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The mr William two questions please!

melamori03 [73]

well, in short, the students and chaperones are at a 2 : 9 ratio, and we know there are 171 students, how many chaperones then, so long they maintain a 2:9 ratio?

$\bf \cfrac{chaperones}{students}\qquad 2:9\qquad \cfrac{2}{9}\qquad \qquad \cfrac{x}{171}=\cfrac{2}{9}\implies 9x=2(171) \\\\\\ 9x=342\implies x=\cfrac{342}{9}\implies x=38$

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3 years ago