The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.
<h3>What is the Nernst Equation?</h3>
The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:
![\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}](https://tex.z-dn.net/?f=%5Cmathbf%7BE_%7Bcell%7D%20%3D%20E_o%20-%20%5Cdfrac%7B0.059%7D%7Bn%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%2B%5D%7D%7B%5BMn%5E%7B2%2B%7D%5D%7D%7D)
where;
- n = Number of electrons = 2
= Initial voltage = 0.77 V
= Cell voltage = 0.78 V![\mathbf{[Mn^{2+}]}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5BMn%5E%7B2%2B%7D%5D%7D)
= Manganese concentration = 0.050 M
Replacing the values into the above equation, we have:
![\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7B0.78%20%3D%200.77%20-%20%5Cdfrac%7B0.059%7D%7B2%7D%20%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
![\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7B0.78%20-0.77%3D%20-0.0296%5Ctimes%20log%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
![\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}](https://tex.z-dn.net/?f=%5Cmathbf%7Blog%5E%7B-1%7D%20%28-0.3378%29%20%3D%20%5Cdfrac%7B%5BFe%5E%7B2%2B%7D%5D%7D%7B%5B0.050%5D%7D%7D)
Learn more about using the Nernst equation here:
brainly.com/question/24258023
Manifestations associated with hepatic encephalopathy from chronic liver disease are the result of impaired ammonia metabolism.
<h3>
What is hepatic encephalopathy?</h3>
Hepatic encephalopathy is a condition where the brain and nervous system may affect the liver and cause serious disease.
Hepatic encephalopathy may be associated with an altered ammonia metabolism, where the urea is not metabolized properly.
In conclusion, manifestations associated with hepatic encephalopathy from chronic liver disease are the result of impaired ammonia metabolism.
Learn more about hepatic encephalopathy here:
brainly.com/question/6989716
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Answer: C
Explanation: i took the testtttttttt..,
Answer:
I used the function 1-proportion z-interval on the calculator, where I inputted
- Successes(x) = 64
- Sample size(n) = 593
- Confidence Level(C level) = 0.99
It would result in zInterval_1Prop 64,593,0.99: stat.results, where the values are shown below as:
- Lower bound (CLower) = 0.075105
- Upper bound (CUpper) = 0.140747
- test statistic (p^) = 0.107926
- Margin of error (ME) = 0.032821
Therefore, the 99% confidence interval would be around 0.11 ± 0.03 or range from 0.08 to 0.14.
<em><u>Note: not sure if this is correct</u></em><em> O_o</em>
