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lorasvet [3.4K]
3 years ago
6

Write the word sentence as an equation. Then solve.

Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0

Answer:

-3y = -8 then you get your answer from that

Step-by-step explanation:

<u>-3y</u><u> </u>= -8

  1. <u>-3</u><u>. </u><u> </u><u> </u><u> </u><u> </u><u>-3</u>
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In a survey, 32% of people choose applesauce your favorite fruit. 56 people chose apples, how many people were in the survey?
LUCKY_DIMON [66]
There was 175 people in the survey
7 0
3 years ago
A rectangular solid has sides of 10 cm, 6.5cm and 8.3 cm. What is the volume and the surface area?
dangina [55]
Part (1):
Volume of the rectangular prism can be calculated as follows:
volume = length * width * height
We are given the three dimensions, therefore, all we need to do is substitute in the above equation as follows:
volume = 10 * 6.5 * 8.3
volume = 539.5 cm³

Part (2):
Surface area of rectangular prism an be calculated as follows:
Surface area = 2(length*width) + 2(width*height) + 2(length*height)
Surface area = 2(10*6.5) + 2(6.5*8.3) + 2(10*8.3)
Surface area = 130 + 107.9 + 166
Surface area = 403.9 cm²

Hope this helps :)
3 0
4 years ago
CONSTRUCTION You are asked to copy a segment CD, construct a segment bisector by paper folding, and label the
lilavasa [31]

The steps on the construction of a segment bisector by paper folding, and label the midpoint M is given below.

<h3>What are the steps of this construction?</h3>

1. First, one need to open a Compass so that it is said to be more than half the length of the said segment.

2. Without altering it, with the aid of the compass, do  draw an art above and also below the said line segment from one of the segment endpoints.

3. Also without altering it and with use the compass, do draw another pair of arts from the other and points. One arc will be seen above the segment and the other or the second arc will be seen below.

4. Then do draw the point of intersection that is said to exist between the pair of arts below the line segment and also in-between the pair of arts as seen  below the line segment

5. Lastly, do make use of a straight edge to link the intersection points between the both pair of arts.

Learn more about segment bisector from

brainly.com/question/24736149

#SPJ1

5 0
2 years ago
Help pls I'll give 25 points
RideAnS [48]

Answer:

\text{C. }60

Step-by-step explanation:

<u>Question from image</u>:

"The digits 1, 2, 3, 4, and 5 can be formed to arrange 120 different numbers. How many of these numbers will have the digits 1 and 2 in increasing order? For example, 14352 and 51234 are two such numbers."

Let's start by taking a look with the number 1. There are four possible places 1 could be, because there needs to be space for the 2 after it.

Checkmarks mark where the 1 can be, the <em>x</em> marks where it cannot be.

\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{X}

Let's start with the first position:

\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are four places the 2 can be. For each of these four places, we can arrange the remaining 3 digits in 3!=6 ways. Therefore, there are 4\cdot 6=\boxed{24} possible numbers when 1 is the first digit of the number.

Continue this process with the remaining possible positions for 1.

Second position:

\underline{X}\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are three places the 2 can be, since the 2 must be behind the 1. For each of these three places, the remaining 3 digits can be arranged in 3!=6 ways. Therefore, there are 3\cdot 6=\boxed{18} possible numbers when 1 is the second digit of the number.

The pattern continues. Next there will be 2 places to place the 2. For each of these, there are 3!=6 ways to rearrange the remaining 3 digits for a total of 2\cdot 6=\boxed{12} possible numbers when 1 is the third digit of the number.

Lastly, when 1 is the fourth digit of the number, there is only 1 place the 2 can be. For this one place, there are still 3!=6 ways to rearrange the remaining three numbers. Therefore, there are 1\cdot 6=\boxed{6} possible numbers when 1 is the fourth digit of the number.

Thus, there are 24+18+12+6=\boxed{60} numbers that will have the digits 1 and 2 in increasing order, from a set of 120 five-digit numbers created by the digits 1 through 5, where no digit may be repeated.

5 0
3 years ago
Drag each tile to the correct box. Arrange the equations in order from least to greatest bed on their solution. Equation A: 5( x
olya-2409 [2.1K]

Answer:

B

C

A

Step-by-step explanation:

Find the value of x in each equation then compare the solutions from the least to the greatest

<u>In A</u>

5( x-6)+3x=3/4(2x-8) ------------Open brackets

5x-30+3x=3/2x-6

5x+3x-30=3/2x-6

8x-3/2x=-6+30---------------collect like terms

16x-3x=48

13x=48-----------------dived both sides by 13

x=48/13 = 3.7

<u>In B</u>

2.7(5.1x+4.9)=3.2+28.9-------------open bracket

13.77x+13.23=32.1

13.77x=32.1-13.23---------------collect like terms

13.77x=18.87

x=18.87/13.77----------------------divide both sides by 13.77

x=1.37

<u>In C</u>

5(11x-18)=3(2x+7)--------------------open brackets

55x-90=6x+21

55x-6x=21+90-----------------------collect like terms

49x=111----------------------------------divide both sides by 49 to get x

x=111/49 = 2.27

From the solutions, the least value of x is in B, then C ,and finally A

6 0
4 years ago
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