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Reptile [31]
3 years ago
5

Help pls I'll give 25 points

Mathematics
1 answer:
RideAnS [48]3 years ago
5 0

Answer:

\text{C. }60

Step-by-step explanation:

<u>Question from image</u>:

"The digits 1, 2, 3, 4, and 5 can be formed to arrange 120 different numbers. How many of these numbers will have the digits 1 and 2 in increasing order? For example, 14352 and 51234 are two such numbers."

Let's start by taking a look with the number 1. There are four possible places 1 could be, because there needs to be space for the 2 after it.

Checkmarks mark where the 1 can be, the <em>x</em> marks where it cannot be.

\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{X}

Let's start with the first position:

\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are four places the 2 can be. For each of these four places, we can arrange the remaining 3 digits in 3!=6 ways. Therefore, there are 4\cdot 6=\boxed{24} possible numbers when 1 is the first digit of the number.

Continue this process with the remaining possible positions for 1.

Second position:

\underline{X}\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}

There are three places the 2 can be, since the 2 must be behind the 1. For each of these three places, the remaining 3 digits can be arranged in 3!=6 ways. Therefore, there are 3\cdot 6=\boxed{18} possible numbers when 1 is the second digit of the number.

The pattern continues. Next there will be 2 places to place the 2. For each of these, there are 3!=6 ways to rearrange the remaining 3 digits for a total of 2\cdot 6=\boxed{12} possible numbers when 1 is the third digit of the number.

Lastly, when 1 is the fourth digit of the number, there is only 1 place the 2 can be. For this one place, there are still 3!=6 ways to rearrange the remaining three numbers. Therefore, there are 1\cdot 6=\boxed{6} possible numbers when 1 is the fourth digit of the number.

Thus, there are 24+18+12+6=\boxed{60} numbers that will have the digits 1 and 2 in increasing order, from a set of 120 five-digit numbers created by the digits 1 through 5, where no digit may be repeated.

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Help me answer pls thanks.Dont answer if ur just put nothing or you dont know. ​
raketka [301]
Hi I want the points thanks
8 0
2 years ago
The ratio of boys to girls in class is 4 : 5 <br> What fraction of the class are boys
Sav [38]

Answer:

The ratio of boys to girls is 4:5. So let 4x be the number of boys and 5x be the number of girls. Then 4x+5x = 9x is the total number of students. Then the fraction of boys in the class is 4x/9x = 4/9.

6 0
3 years ago
Is this a linear function ?<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20-%203%20%5E%7B2%7D%20%20%2B%202" id="TexFormula1"
Slav-nsk [51]
No its not a linear function i think
8 0
3 years ago
Please help me with this
sesenic [268]
Ok so the average is 50

average of x number of things is
(add value of all things)/x=average

4 test scores needed
so divide by 4
3 test scores ar known
average is 50
x= missing score

(43+48+42+x)/4=50
times 4 both sides
133+x=200
minus 133 both sides
x=67

a score of 67 is needed
5 0
3 years ago
A line in the xy-plane that passes through the coordinate points (3, -6) and (–7, –4) will never intersecta line that is represe
anyanavicka [17]

Answer:

option A

Step-by-step explanation:

given coordinate (3, -6) and (–7, –4)

to find the equation of line

slope of the line passing through both the point will be

               m = \dfrac{y_2-y_1}{x_2-x_1}

               m = \dfrac{-4+6}{-7-3}

               m = -\dfrac{2}{10}

equation of line

( y - y₁ ) = m ( x - x₁ )

y + 6= -\dfrac{2}{10}(x - 3)

x + 5 y = -27

line which will not intersect will be parallel to it so option A has same slope as our line equation i.e. -1/5

hence, correct answer is option A

3 0
3 years ago
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