For this case , the parent function is given by [tex f (x) =x^2
[\tex]
We apply the following transformations
Vertical translations :
Suppose that k > 0
To graph y=f(x)+k, move the graph of k units upwards
For k=9
We have
[tex]h(x)=x^2+9
[\tex]
Horizontal translation
Suppose that h>0
To graph y=f(x-h) , move the graph of h units to the right
For h=4 we have :
[tex ] g (x) =(x-4) ^ 2+9
[\tex]
Answer :
The function g(x) is given by
G(x) =(x-4)2 +9
Answer:
73.6
Step-by-step explanation:
64x15%=9.6
9.6+64=73.6
Answer:
2/3
Step-by-step explanation:
so the inverse takes us from the range to the domain... they tell us that f(4) goes to 5.. so if we were to take the inverse f
(5) it takes us back to 4... and the slope at 4 or the derivative was 2/3 so that's what we get for f
'(5) :)
Answer:
The sweat chloride reference value is less than 30 mmol/L. A value of more than 60 mmol/L of chloride in the sweat is consistent with a diagnosis of cystic fibrosis. The values of 30-60 mEq/L may represent heterozygous carriers, these carriers cannot be accurately identified with a sweat chloride test.
