<span> half life i= 78 hours
amount after 78 hours is 395 kg:
395 = 790e^(k*78)
Dividing by 790 and taking natural log
ln (395/790) = (k*78)
-0.6931 = 78k
-0.00888 = k
lets calculate how much is left after 18 hours:
Amount(18)
= 790e^(-0.00888*18)
Amount = 673.301 kg
hope this helps</span>
The margin of error given the proportion can be found using the formula

Where

is the z-score of the confidence level

is the sample proportion

is the sample size
We have



Plugging these values into the formula, we have:

The result 0.14 as percentage is 14%
Margin error is 38% ⁺/₋ 14%
What is the interquartile range for the data set 4,7,7,3,5,2,6,7,9 the answers are 3.5, 5.6, 7,9
polet [3.4K]
5.6 is the answer for your question
Correct answer is the last one.
-4.16 is your answer and I have to fill up space to submit this