What is the answer to ax-8b=c

Araceli made 9 identical bags using 4 yards of fabric. How much fabric did Araceli use for each bag?

miv72 [106K]

Answer:

Araceli would have used 2.25 (or 2 1/4) yards of fabric for each bag.

Step-by-step explanation:

First, you have the 9 bags you are making and they all must be the same because they are identical, so you divide the nine bags by the four yards and I got an answer of 2.25 yards per bag. The answer can also be 2 1/4 as well.

7 0

3 years ago

Read 2 more answers

The coordinates of which point are (–3, –6)? On a coordinate plane, point A is (negative 3, 6), point B is (negative 6, negative

lana [24]

Given:

The coordinates of a point are (-3,-6).

To find:

The point on the coordinate plane whose coordinates are (-3,-6).

Solution:

From the given information of coordinate plane, it is clear that

Coordinates of point A are (-3, 6).

Coordinates of point B are (-6,-3)

Coordinates of point C are (-3,-6)

Coordinates of point D are (3,-6)

It is clear that, only point C has coordinates (-3,-6).

So, the required point is C.

Therefore, the correct option is C.

8 0

3 years ago

Read 2 more answers

the ratio of men to women at Wal-Mart was 3 to 5. If there were 350 women, How many men were in the store?

kirill [66]

Answer:550

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

3 years ago

If f(x)=3x^2+1 and g(x)=1-x, what is the value of (f-g)(2)?

madam [21]

The answer is 14 you just have to substitute x with the given number and finish the equation

3 0

3 years ago

Read 2 more answers