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Diano4ka-milaya [45]
2 years ago
6

The weight of people in a small town in Missouri is known to be normally distributed with a mean of 162 pounds and a standard de

viation of 28 pounds. On a raft that takes people across the river, a sign states, “Maximum capacity 3,401 pounds or 19 persons.” What is the probability that a random sample of 19 persons will exceed the weight limit of 3,401 pounds?
Mathematics
1 answer:
never [62]2 years ago
8 0

Using the normal distribution relation, the probability that sample will exceed the weight limit is 0.004

<u>Using the relation</u> ::

  • Zscore =(X - μ) ÷ σ

The mean, μ = np = (162 × 19) = 3078

The standard deviation, σ = 28 × √19 = 122.049

<u>The Zscore</u> :

Zscore = (3401 - 3078) ÷ (122.049)

Zscore = 2.65

Hence,

P(Z > 2.65) = 1 - P(Z < 2.65)

Using a normal distribution table :

P(Z > 2.65) = 1 - 0.9959

P(Z > 2.65) = 0.004

Learn more : brainly.com/question/25204474

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A) given that in 2019 you were among the 21.11% of the best students in the class, in that year you had the higher percentile ranking, and B) the measure of average that would be the most meaningful is the median.

Given that your class rank in 2018 was 89 out of 360 students, while in 2019 your class rank was 95 out of 450 students, to determine A) in which year did you have the higher percentile ranking, and B) if you had the data on the cumulative GPA of each student at the end of the spring semester in 2018, which measure of average would be the most meaningful - mean, median or mode -, the following calculation should be performed:

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