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3 years ago

Find a solution to the linear equation y equals 8x-32

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

7 0

The solution to this linear equation is x = y + 32. Explanation and answer is in the image below.

Lerok [7]3 years ago

4 0

Answer:

(4, 0).

Step-by-step explanation:

y = 8x - 32

There are many solutions that we can choose from, since any set of coordinates that fit in the equation counts as a solution.

We can have (0, -32), (1, -24), (2, -16), (3, -8), (4, 0), and many more.

Hope this helps!

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4 years ago

The endpoints of CD are C(–8, 4) and D(6, –6). What are the coordinates of point P on CD such that P is the length of the line s

Arturiano [62]

If you graph the end points C and D then graph the 4 points at the end it is difficult to tell which points are on CD without a line.
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I am confused by the part, "P is the length of the line segment from D". Were you given a length P to help you determine which point. Using the distance formula to find the length from each point to D doesn't help determine which one is best with the information you have given. The image shows the distances I calculated and the graphed points.
I hope this helps!

3 0

3 years ago

Read 2 more answers

When the population distribution is normal, the statistic median {|X1 − X tilde|, . . . , |Xn − X tilde|}/0.6745 can be used to

Andreyy89

Answer:

The corresponding point estimate is 0.882.

The sample standard deviation is 1.373.

Step-by-step explanation:

The data set is:

S = {25.01, 25.87, 26.34, 26.51, 26.75, 27.24, 27.40, 27.63, 27.83, 27.90, 28.08, 28.13, 28.37, 28.58, 28.59, 28.96, 29.20, 29.22, 29.38, 30.88}

Compute the mean as follows:

$\bar X=\frac{1}{n}\sum X\\\\=\frac{1}{20}\times [25.01+25.87+...+30.88]\\\\=\frac{1}{20}\times 557.87\\\\=27.8935$

Subtract the mean from each value and take the modulus of those values.

The new data set is:

S₁ = {2.8835, 2.0235, 1.5535, 1.3835, 1.1435, 0.6535, 0.4935, 0.2635, 0.0635, 0.0065, 0.1865, 0.2365, 0.4765, 0.6865, 0.6965, 1.0665, 1.3065, 1.3265, 1.4865, 2.9865}

Arrange these values in ascending order as follows:

S₂ = {0.0065 , 0.0635 , 0.1865 , 0.2365 , 0.2635 , 0.4765 , 0.4935 , 0.6535 , 0.6865 , 0.6965 , 1.0665 , 1.1435 , 1.3065 , 1.3265 , 1.3835 , 1.4865 , 1.5535 , 2.0235 , 2.8835 , 2.9865}

There are 20 observations in the data set.

The median value for an even set of values is the mean of the middle two values.

In this case the median will be the mean of the 10th and 11th observations.

$\text{Median}=\frac{10^{th}obs.+11^{th}obs.}{2}=\frac{0.6965+1.0665}{2}=0.8815\approx 0.882$

Thus, the corresponding point estimate is 0.882.

Compute the standard deviation as follows:

In set S₁ we computed the absolute mean deviations.

Now take the square of these values and divide by (n - 1) to compute the sample variance:

$\sigma^{2}=\frac{1}{n-1}\sum (|X_{i}-\bar X|)^{2}$

$=\frac{1}{20-1}\times [(2.8835)^{2}+(2.0235)^{2}+...+(2.9865)^{2}]\\\\=\frac{1}{19}\times 35.7953\\\\=1.88396$

Compute the sample standard deviation as follows:

$\sigma=\sqrt{\sigma^{2}}=\sqrt{1.88396}=1.373$

Thus, the sample standard deviation is 1.373.

6 0

3 years ago