All categories

2 years ago

Find a solution to the linear equation y equals 8x-32

Mathematics

2 answers:

MA_775_DIABLO [31]2 years ago

7 0

The solution to this linear equation is x = y + 32. Explanation and answer is in the image below.

Lerok [7]2 years ago

4 0

Answer:

(4, 0).

Step-by-step explanation:

y = 8x - 32

There are many solutions that we can choose from, since any set of coordinates that fit in the equation counts as a solution.

We can have (0, -32), (1, -24), (2, -16), (3, -8), (4, 0), and many more.

Hope this helps!

You might be interested in

Okay so we have this question of the week thing and this week our answer is 8 so i need a algebra problem that is a two step equ

Inessa05 [86]

Answer:

2x+4=8

x=2

2 times 2 equals 4

Four plus four is 8

5 0

3 years ago

A city planner wants to build a road parallel to 2nd Ave . What is the slope of the new road?

jenyasd209 [6]

Answer: no idea

Step-by-step explanation:

5 0

3 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

3 years ago

Find the outlier of the set of data: 24,18, 33, 20, 18, 24, 8, 24

sertanlavr [38]

8, because it's the has the greatest difference from the number average.

3 0

2 years ago

Read 2 more answers

One technique of killing cancer cells involves inserting microscopic synthetic rods, called carbon nanotubules, into the cell. W

Vlad [161]

Answer:

The probability that the cell will be killed is 0.9328.

Step-by-step explanation:

We are given that five nanotubules are inserted in a single cancer cell. Independently of each other, they become exposed to near-infrared light with probabilities 0.2, 0.4, 0.3, 0.6, and 0.5.

Let the event that a cell is killed be 'A' and the event where the ith nanotubule kill the cell be ' $\text{B}_i$ '.

This means that the cell will get killed if $\text{B}_1 \bigcup \text{B}_2 \bigcup \text{B}_3 \bigcup \text{B}_4 \bigcup \text{B}_5$ happens. This represents that the cell is killed if nanotubule 1 kills the cell, or nanotubule 2 kills the cell, and so on.