Let n (AUB)=32n(B)=16and n(ANB)9 find n (A)
2 answers:
Answer:
n(A) = 25
Step-by-step explanation:
The relation between cardinality of two sets and that of their union and intersection is ...
n(A∪B) = n(A) +n(B) -n(A∩B)
32 = n(A) +16 -9 . . . . . use the given information
25 = n(A) . . . . . . . . . subtract 7
Answer:
32
Step-by-step explanation:
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)= ? we represent with x
n(B)= 16
n(A∪B) = 32
Substituting in equation 1 to get n(A)
32 = n(A) + 9 − 9
⇒n(A) = 32 − 0
n(A) = 32
to confirm this we put the values into the formula below
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
32 = 32 + 9 - 9
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