solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
Answer:
A) . (0, -20) I hope this is right.
Answer:
See my explanation below.
Step-by-step explanation:
Let's start with two random mixed numbers.
÷
The first step is starting with . Think about going from the denominator to the number on the left. After you remember that rule multiply 4 by 5. You should get 20. After that, you add by the numerator. 20 + 3=23
This is how it would be written.
Do the same for the next mixed number. 5 x 4 = 20 and add by the numerator 21.
After this is done. You will multiply by those fractions. x = we would write it as as a mixed fraction.
I hope this helps!
5.93 > 5.917 is true so there are infinitely many solutions.
Answer:
36
Step-by-step explanation:
5/8 x 32/5 = 2
2 x 18 = 36