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3 years ago

5

Assume that 10% of people are left-handed. suppose 12 people are selected at random. what's the probability that the majority

is right-handed?

1 answer:

Zepler [3.9K]3 years ago

5 0

There might just be 1. try multiplying percentage by the number of people

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Find the integer that makes this subtraction statement true -3 - ? = -5

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Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{2}}}}}$

Step-by-step explanation:

Let the missing integer be x

Solve for x

$\sf{ - 3 - x = - 5}$

Move 3 to right hand side and change it's sign

$\dashrightarrow{ \sf{ - x = - 5 + 3}}$

The negative and positive integers are always subtracted but posses the sign of the bigger integer

$\dashrightarrow{ \sf{ - x = - 2}}$

Change the signs of both sides

$\dashrightarrow{ \boxed{ \sf{x = 2}}}$

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