Assume that 10% of people are left-handed. suppose 12 people are selected at random. what's the probability that the majority
is right-handed?
1 answer:
There might just be 1. try multiplying percentage by the number of people
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Answer:
1 2 5
Step-by-step explanation:
right I got it right on the test
Step-by-step explanation:
Answer is attached....of both the parts.
Hope it helps:)
To find the percent, we do:
200/740=0.27←Find it in decimal form
0.27×100=27%←Multiply using 100 to find the percentage.
So n will be the unknown, and the expression is:
6n = 24
from where we can find the number n:
n = 24/6
n = 4
Answer:7 + 11x
Step-by-step explanation: you add your letter and number that were in the brackets the since 7 has no number the equation would end and become 7+11x
