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lianna [129]
2 years ago
13

4

Mathematics
1 answer:
scZoUnD [109]2 years ago
3 0

Answer:

density=mass/volume:514g/500cm cubic

=1.028g/cubic centimeters

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Please help me!!!<br><br> Hhhhhhhhhhhhhh
vekshin1

Answer:

C: -|x| + 3

Step-by-step explanation:

From the graph, we see that when y = 2, x is either +1 or -1

Also,when y = 1, x = +2 or -2

Thus,we can say that;

y = (-x) + 3 or -(x - 3)

So, we can write this in absolute value form as; y = -|x| + 3

4 0
3 years ago
If PN=29cm and MN=13 , then PM=?
HACTEHA [7]

*see attachment for the figure referred to

Answer/Step-by-step explanation:

1. PN = 29

MN = 13

PM = ?

PN = PM + MN (Segment addition postulate)

PN - MN = PM (subtract MN from each side)

29 - 13 = PM (substitute)

16 = PM

PM = 16 cm

2. PN = 34, MN = 19, PM = ?

PN = PM + MN (sediment addition postulate)

PN - MN = PM (subtract MN from each side)

34 - 19 = PM (substitute)

15 = PM

PM = 15 cm

3. PM = 19, MN = 23, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 19 + 23 (substitute)

PN = 42 cm

4. MN = 82, PN = 105, PM = ?

PN = PM + MN (segment addition postulate)

PN - MN = PM (subtract MN from each side)

105 - 82 = PM (substitute)

23 = PM

PM = 23 cm

5. PM = 100, MN = 100, PN = ?

PN = PM + MN (Segment addition postulate)

PN = 100 + 100 (substitute)

PN = 200 cm

7 0
3 years ago
You have a 1-gallon paint can in the shape of a cylinder. One gallon is 231 cubic inches. The radius of the can is 3 inches. Wha
aleksandr82 [10.1K]

Answer:

The approximate height of the paint can is 8.2 in

Step-by-step explanation:

we know that

The volume of the cylinder ( can of paint) is equal to

V=\pi r^{2} h

we have

V=231\ in^{3}

r=3\ in

\pi=3.14

Substitute the values and solve for h

231=(3.14)(3)^{2} h

h=231/(3.14*9)=8.2 in

3 0
3 years ago
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Irina18 [472]
The perimeter would be 84
8 0
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