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Wewaii [24]
2 years ago
13

Slope of the line (0,7), (4,4)

Mathematics
2 answers:
devlian [24]2 years ago
7 0

Answer:

Your slope is always \frac{y2-y1}{x2-x1}, so your equation would be \frac{4-7}{4-0} = \frac{-3}{4}

Step-by-step explanation:

belka [17]2 years ago
5 0

Answer:

-3/4

Step-by-step explanation:

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WHY CAN'T ANYONE HELP ME? :( Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and
devlian [24]

Answer:

Children: $13

Adults: $18

Step-by-step explanation:

Well for both sets we can set up the following system of equations,

\left \{ {{3a + 4c = 106} \atop {2a + 3c = 75}} \right.

So first we need to solve for a in the first equation.

3a + 4c = 106

-4c to both sides

3a = -4c + 106

Divide 3 by both sides

<u>a = -4/3c + 35 1/3</u>

Now we plug in that a for a in 2a + 3c = 75.

2(-4/3c + 35 1/3) + 3c = 75

-8/3c + 70 2/3 + 3c = 75

Combine like terms

1/3c + 70 2/3 = 75

-70 2/3 to both sides

1/3c = 4 1/3

Divide 1/3 to both sides

c = 13

Now we can plug in 13 for c in 3a + 4c = 106,

3a + 4(13) = 106

3a + 52 = 106

-52 to both sides

3a = 54

Divide 3 by both sides.

a = 18

<em>Thus,</em>

<em>an adult ticket is $18 and a children's ticket is $13.</em>

<em />

<em>Hope this helps :)</em>

5 0
3 years ago
Read 2 more answers
Solve the following equation for s P=b+2s
laiz [17]

Answer:

s=P-b/2

Step-by-step explanation:

P-b=2s

P-b/2=s

3 0
3 years ago
Consider the function below, which has a relative minimum located at (-3 , -18) and a relative maximum located at (1/3, 14/17).
leonid [27]
First of all, when I do all the math on this, I get the coordinates for the max point to be (1/3, 14/27).  But anyway, we need to find the derivative to see where those values fall in a table of intervals where the function is increasing or decreasing.  The first derivative of the function is f'(x)=-3x^2-8x+3.  Set the derivative equal to 0 and factor to find the critical numbers. 0=-3x^2-8x+3, so x = -3 and x = 1/3.  We set up a table of intervals using those critical numbers, test a value within each interval, and the resulting sign, positive or negative, tells us where the function is increasing or decreasing.  From there we will look at our points to determine which fall into the "decreasing" category.  Our intervals will be -∞<x<-3, -3<x<1/3, 1/3<x<∞.  In the first interval test -4. f'(-4)=-13; therefore, the function is decreasing on this interval.  In the second interval test 0. f'(0)=3; therefore, the function is increasing on this interval.  In the third interval test 1. f'(1)=-8; therefore, the function is decreasing on this interval.  In order to determine where our points in question fall, look to the x value.  The ones that fall into the "decreasing" category are (2, -18), (1, -2), and (-4, -12).  The point (-3, -18) is already a min value.
8 0
3 years ago
How do I do this. I don’t understand how to put the numbers in that formula or whatever the heck it is.
OleMash [197]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
2. Any number that can result from
Alla [95]
Multiple im pretty sure- Well, a multiple is any number obtained by multiplying other numbers together. Multiples are most commonly discussed in the context of integers.
8 0
3 years ago
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