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3 years ago

Two numbers have a sum of 12 and a difference of 4. What is the smaller of the two numbers?

Mathematics

2 answers:

ehidna [41]3 years ago

6 0

Answer:

Step-by-step explanation:

PSYCHO15rus [73]3 years ago

5 0

Answer:

Explaining :

4/12 is 8

8+4=12

12-4=8

I hope it work :)

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In order to answer the following question, please use the following image down below:

Kryger [21]

Answer:

Step-by-step explanation:

X^2 = (7+9)(9) -->

X^2 = 16(9) -->

X = 12

8 0

3 years ago

In Exercise, evaluate each expression.<br> 643/4

Goshia [24]

Answer:

$\\ 64^{\frac{3}{4}} = 16\sqrt{2}$

Step-by-step explanation:

We need here to remember that:

$\\{(x^{a})}^{b} = x^{a * b}$

$\\{x^{a} * x^{b} = x^{a + b}$

Then,

$\\ 64^{\frac{3}{4}} = {(8^{2})}^{(\frac{3}{4})} = {{(2^{3})}^{2}}^\frac{3}{4}$

$\\ 64^{\frac{3}{4}} = {{2^{3}}^2}^\frac{3}{4} = 2^\frac{3*2*3}{4}$

$\\ 64^{\frac{3}{4}} = 2^\frac{2*3*3}{4} = 2^\frac{3*3}{2} = 2^\frac{9}{2}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{9}{2}}$

Since $\\ \frac{9}{2} = \frac{4}{2} + \frac{4}{2} + \frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{9}{2}} = {2^{(\frac{4}{2} + \frac{4}{2} + \frac{1}{2})}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{4}{2}} * 2^{\frac{4}{2}} * {2}^{\frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 2^{2} * 2^{2} * {2}^{\frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 4 * 4 * \sqrt{2} = 16 \sqrt{2}$

5 0

3 years ago

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Evgen [1.6K]

Answer:

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Step-by-step explanation:

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3 years ago

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Twice a number diminished by seven

makvit [3.9K]

Answer:

2x-7

Step-by-step explanation:

let the no be X

twice the no =2X

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3 years ago

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A right triangle has sides of length 3, 4, and x. Find x if it is one of the legs

lianna [129]

I think it might be 5, because it is a pythagrum triple

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3 years ago