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Vesna [10]
3 years ago
8

find the slope intercept form for the equation of a line which passes through the point( 7, 4) and the origin​

Spanish
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

y = \frac{4}{7}x

Explanation:

Slope-intercept form is y = mx + b

m is the slope (rise over run)

b is the y-intercept (where the line crosses the y-axis)

To get the slope, use the formula \frac{y_{2} - y_{1} }{x_{2} - x_{1}}. It doesn't matter which set of coordinates is which pair.

(x₁,y₁) = (7,4)

(x₂,y₂) = (0,0)  a.k.a "the origin"

\frac{0-4}{0-7} = \frac{-4}{-7} = \frac{4}{7} = your slope (m)

Now, to get to slope-intercept form, you have to plug what you know into point-slope form, y - y₁ = m(x - x₁).

y₁ = a point on the line

m = slope

x₁ = the matching coordinate to y₁

y - 4 = \frac{4}{7} (x - 7)   Distribute

y - 4 = \frac{4}{7} x - \frac{4*7}{7}   Simplify

y - 4 = \frac{4}{7}x - 4   Add 4 to both sides

y = \frac{4}{7}x + 0 or y = \frac{4}{7}x

Check your work by plugging in your given coordinates:

y = \frac{4}{7}x

0 = \frac{4}{7}(0)

0 = 0

and

y = \frac{4}{7}x

4 = \frac{4}{7}(7)

4 = \frac{4*7}{7}

4 = 4

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