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3 years ago

Find x so that f(x)=3

Mathematics

1 answer:

dybincka [34]3 years ago

7 0

Answer:

x = 2

Step-by-step explanation:

locate y = f(x) = 3 on the y- axis , go horizontally across to meet the line at

(2, 3 ) , then

when x = 2 , f(x) = 3

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F(x) = -2x^3+6x-4, g(x) = -1/2f(x)

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3 years ago

2 very easy questions for 40 points

Varvara68 [4.7K]

4.a)2x+10 >27
4.b) 27-10= 17
17/2=8.5
3.a) 40-2x>7
3.b) 7-40=-33
-33/-2=16.5
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7 0

3 years ago

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Find the third degree polynomial function that has an output of 40 when x=1, and has zeros −19 and −i?

Yanka [14]

Answer:

$f(x) = (x + 19)(x^2 + 1)$

Step-by-step explanation:

Complex numbers:

The following relation is important for complex numbers:

$i^2 = -1$

Zeros of a function:

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ such that it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

Has zeros −19 and −i

If -i is a zero, its conjugate i is also a zero. So

$f(x) = a(x - (-19))(x - (-i))(x - i) = a(x+19)(x+i)(x-i) = a(x+19)(x^2 - i^2) = a(x + 19)(x^2 + 1)$

Output of 40 when x=1

This means that when $x = 1, f(x) = 40$ . We use this to find the leading coefficient a. So

$f(x) = a(x + 19)(x^2 + 1)$

$40 = a(20)(2)$

$40a = 40$

$a = 1$

The polynomial is:

$f(x) = (x + 19)(x^2 + 1)$

3 0

3 years ago

Bro i will trade my rare brainly username " harmless ' for the username " Brainly " whoever has it let me know wsp

Vera_Pavlovna [14]

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3 0

3 years ago

Transform the equation to isolate x:ax=bx + 1 how is the value of x related to the difference of a and b

Airida [17]

Answer:

x = $\frac{1}{a-b}$

Step-by-step explanation:

Given

ax = bx + 1

Collect the terms in x on the left side by subtracting bx from both sides

ax - bx = 1 ← factor out x from each term on the left side

x(a - b) = 1 ← divide both sides by (a - b)

x = $\frac{1}{a-b}$

4 0

3 years ago

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