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gulaghasi [49]
3 years ago
6

Find x so that f(x)=3

Mathematics
1 answer:
dybincka [34]3 years ago
7 0

Answer:

x = 2

Step-by-step explanation:

locate y = f(x) = 3 on the y- axis , go horizontally across to meet the line at

(2, 3 ) , then

when x = 2 , f(x) = 3

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F(x) = -2x^3+6x-4, g(x) = -1/2f(x)
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3 years ago
2 very easy questions for 40 points
Varvara68 [4.7K]
4.a)2x+10 >27
4.b) 27-10= 17
17/2=8.5
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7 0
3 years ago
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Find the third degree polynomial function that has an output of 40 when x=1, and has zeros −19 and −i?
Yanka [14]

Answer:

f(x) = (x + 19)(x^2 + 1)

Step-by-step explanation:

Complex numbers:

The following relation is important for complex numbers:

i^2 = -1

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Has zeros −19 and −i

If -i is a zero, its conjugate i is also a zero. So

f(x) = a(x - (-19))(x - (-i))(x - i) = a(x+19)(x+i)(x-i) = a(x+19)(x^2 - i^2) = a(x + 19)(x^2 + 1)

Output of 40 when x=1

This means that when x = 1, f(x) = 40. We use this to find the leading coefficient a. So

f(x) = a(x + 19)(x^2 + 1)

40 = a(20)(2)

40a = 40

a = 1

The polynomial is:

f(x) = (x + 19)(x^2 + 1)

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3 years ago
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Transform the equation to isolate x:ax=bx + 1 how is the value of x related to the difference of a and b
Airida [17]

Answer:

x = \frac{1}{a-b}

Step-by-step explanation:

Given

ax = bx + 1

Collect the terms in x on the left side by subtracting bx from both sides

ax - bx = 1 ← factor out x from each term on the left side

x(a - b) = 1 ← divide both sides by (a - b)

x = \frac{1}{a-b}

4 0
3 years ago
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