34 out of 99 how do you turn those in a decimal

The volume of a rectangular prism is given by the expression 10x^3+46x^2-21x-27. The area of the base of the prism is given by t

andrezito [222]

H = V/B

$h = \frac{10x^3+46x^2-21x-27}{2x^2+8x-9} = 5x + 3 \\ \\ c)5x+3

$

The base of the prism is given by the expression 2X^2+8x-9
then c)5x+3

5 0

3 years ago

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Use the regression line for the data in the scatterplot to answer the question. On average, how many more goals will a player sc

kari74 [83]

Answer:

A. 1/2 of a goal

Step-by-step explanation:

Hello!

Given the options:

A. 1/2 of a goal

B. 3/4of a goal

C. 1 goal

D. 4/3 goals

In a linear regression analysis the interpretation of the slope is:

> The modification of the average of Y when X increases one unit.

Given the variables

Y: Goals scored in the tournament.

X: Hours of training.

To calculate the slope, you have to use the y-intercept and choose two pairs of (Y;X) values that correspond to a value on the line, for example (1;1.5) and (2;1.5).

You can calculate the slope as b= ΔY/ΔX

$b= \frac{Y_2-Y_1}{X_2-X_1}= \frac{1.5-1}{1-0} = \frac{0.5}{1}= \frac{1}{2}$

1st value (X₁;Y₁)= (0;1)

2nd value (X₂Y₂)= (1;1.5)

So the average goals a player scores for every additional hour of practice is 1/2.

I hope this helps!

4 0

3 years ago

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An unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6

SIZIF [17.4K]

Answer:

Probability of rolling at least 4 sixes is 0.01696.

Step-by-step explanation:

We are given that an unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6 times.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......$

where, n = number trials (samples) taken = 6 trials

r = number of success = at least 4

p = probability of success which in our question is probability of

rolling a “six", i.e; p = 0.20

Let X = Number of sixes on a die

So, X ~ Binom(n = 6, p = 0.20)

Now, Probability of rolling at least 4 sixes is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = P(X = 4) + P(X = 5) + P(X = 6)

= $\binom{6}{4} \times 0.20^{4} \times (1-0.20)^{6-4}+\binom{6}{5} \times 0.20^{5} \times (1-0.20)^{6-5}+\binom{6}{6} \times 0.20^{6} \times (1-0.20)^{6-6}$

= $15 \times 0.20^{4} \times 0.80^{2}+6 \times 0.20^{5} \times 0.80^{1}+1 \times 0.20^{6} \times 0.80^{0}$

= 0.0154 + 0.00154 + 0.000064

= 0.01696

Therefore, probability of rolling at least 4 sixes is 0.01696.

8 0

3 years ago

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amm1812

The answer is -28/3 or 9.33333333333 have a great day also could I get brainliest

6 0

3 years ago

If c(x) = 4x − 2 and d(x) = x² + 5x, what is (c.d)(x)?

snow_lady [41]

Answer:

$4x^2+20x-2$

Step-by-step explanation:

To find (c.g)(x) we basically use the function d(x) as your variable, x, and plug it into c(x). So we replace every x in c(x) with the function d(x), $x^{2} +5x$

c(g(x))=4(x^{2} +5x)-2

c(g(x))4 $x^2$ +20x-2

6 0

2 years ago